Export Mysql Table to CSV Using PHP - What's Wrong?

I liked this example because it was intuitive and matched my needs: http://www.a2zwebhelp.com/export-data-to-csv

Problem is, it's using mysql as opposed to mysqli so here's what I've got:

set_time_limit(600);
include ("carter.inc");
$cxn = mysqli_connect($host,$user,$password,$database)
or die ("couldn't connect to server");

$output="";

$michelle="select * from verizon_test order by id";
$michelle_query=mysqli_query($cxn, $michelle)
or die("Michelle didn't work");
$michelle_columns=mysqli_field_count($cxn);

//gets the field names from your table and sets them up as the first row in your csv file

for($i=0; $i<$michelle_columns; $i++)
{
$heading=mysqli_fetch_fields($michelle_query);
$output	.='"'.$heading.'",';
}
$output.="\n";

/*
while($michelle_row=mysqli_fetch_array($michelle_query))
{
	for($i=0; $i<$michelle_columns; $i++)
	{
		$output .='"'.$michelle_row["$i"].'",';
	}
$output.="\n";
}

$filename="json.csv";
header('Content-type:appliation/csv');
header('Content-Dispoition: attachment; filename='.$filename);

echo $output;
exit;*/

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There's more than one problem here, but the first thing I want to tackle is my column names.

The example I liked is using a deprecated function, but I can't figure out how to get mysqli_fetch_fields working. I know it's supposed to be an array, but every time I try to write it as $heading=mysqli_fetch_fields($michelle_query, $i), I get "Warning: mysqli_fetch_fields() expects exactly 1 parameter, 2 given in C:\wamp\www\json\csv_test.php on line 19"

Where am I blowing it?
Bruce GustPHP DeveloperAsked:
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Ray PaseurCommented:
I cannot test this, but it should be about right in principle.
set_time_limit(600);
include ("carter.inc");
$cxn = mysqli_connect($host,$user,$password,$database)
or die ("couldn't connect to server");

$output="";

$michelle="select * from verizon_test order by id";
$michelle_query=mysqli_query($cxn, $michelle)
or die("Michelle didn't work");
$michelle_columns=mysqli_field_count($cxn);

$filename="json.csv";

// OPEN THE CSV FILE HERE
$file = fopen($filename, 'w');

// GET THE FIELD NAMES
$heading=mysqli_fetch_fields($michelle_query);
fputcsv($file, $heading);

// GET THE DATA SET
while($michelle_row=mysqli_fetch_assoc($michelle_query))
{
    fputcsv($file, $michelle_row);
}

// REWIND THE CSV FILE HERE
rewind($file);

// SEND HEADERS AND DATA
header('Content-type:application/csv');
header('Content-Disposition: attachment; filename='.$filename);

fpassthru($file);

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Bruce GustPHP DeveloperAuthor Commented:
Ray!

I'm getting an error at line 20: "fputcsv() expects parameter 1 to be resource, string given in C:\wamp\www\json\csv_test.php on line 20"

What am I missing?
Ray PaseurCommented:
Don't know - I can't test the code I posted.  Suggest you use var_dump() to print out the variables that are used on line 20.
Slick812Commented:
greetings, in your code starting on line 11, you have it all mixed up, incorrect as this errors -
$michelle_columns=mysqli_field_count($cxn);
//gets the field names from your table and sets them up as the first row in your csv file
for($i=0; $i<$michelle_columns; $i++)
{
$heading=mysqli_fetch_fields($michelle_query);
$output	.='"'.$heading.'",';
}

Open in new window


using the for loop in MySQLI does NOT get you the column names, the code below may be more correct if you can correctly substitute it for the bad code you use

Bettre Code bellow.
$heading = mysqli_fetch_fields($michelle_query);

foreach ($heading as $val) {
  $output	.='"'.$val->name.'",';
    }
$output.="\n";

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just so you may know, this line returns an ARRAY -
$heading = mysqli_fetch_fields($mich);
The $heading array has ONE element added for each column in the select,
so if select returns 4 columns then this array has 4 parts, elements. . . .
each element is a php object, that has several properties, like name, table and type, you can access these like -
$name = $heading[0]->name;

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