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Why am I not getting any data in this CSV file?

Posted on 2014-09-25
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Last Modified: 2014-09-25
Here's my code:

error_reporting(E_ALL);

set_time_limit(600);
include ("carter.inc");
$cxn = mysqli_connect($host,$user,$password,$database)
or die ("couldn't connect to server");

$output="";

$michelle="select * from verizon_test order by id";
$michelle_query=mysqli_query($cxn, $michelle)
or die("Michelle didn't work");
$michelle_columns=mysqli_field_count($cxn);

//gets the field names from your table and sets them up as the first row in your csv file

$heading=mysqli_fetch_fields($michelle_query);

foreach ($heading as $val)
{
	$output .='"'.$val->name .'",';
}
$output .="\n";


while($michelle_row=mysqli_fetch_array($michelle_query))
{
	for($i=0; $i<$michelle_columns; $i++)
	{
		$output .='"'.$michelle_row["$i"].'",';
	}
$output .="\n";
}

$filename="json.csv";
header('Content-type:appliation/csv');
header('Content-Disposition: attachment; filename='.$filename);

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No errors, but no data. What am I doing wrong?
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Question by:brucegust
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2 Comments
 
LVL 34

Accepted Solution

by:
Slick812 earned 2000 total points
ID: 40344732
you may need to accually OUTPUT the Memory of the variable $output
with

echo $output;

after it is completed it's additions. This is configured to be a downloaded file, I guess you know that.
0
 

Author Comment

by:brucegust
ID: 40344787
Well, that would make a difference!

Thanks!

BTW: More input would be needed at http://www.experts-exchange.com/Programming/Languages/Scripting/PHP/Q_28525824.html
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