Solved

Fatal error: Can't use function return value in write context

Posted on 2014-09-26
6
871 Views
Last Modified: 2014-09-26
Hi Experts,

Why do I keep getting:
Fatal error: Can't use function return value in write context

...when I:
   if(isset($_POST["email"]) || !empty(trim($_POST["email"])))
   {
       $strEmail = $_POST["email"];
   }
   else 
   {
       $err = 1;
   }

Open in new window


Thank you.
0
Comment
Question by:APD_Toronto
6 Comments
 
LVL 58

Expert Comment

by:Gary
ID: 40346657
if(isset($_POST["email"]) && !empty(trim($_POST["email"])))
0
 

Author Comment

by:APD_Toronto
ID: 40346664
makes logical sense - thanks, but same error
0
 
LVL 58

Expert Comment

by:Gary
ID: 40346668
What is the whole function
0
Live: Real-Time Solutions, Start Here

Receive instant 1:1 support from technology experts, using our real-time conversation and whiteboard interface. Your first 5 minutes are always free.

 

Author Comment

by:APD_Toronto
ID: 40346673
nothing too complex... The error is at Li.40

<?php

    $submit = '';
    $err = 0;
   
    $strName = '';
    $strEmail = '';
    $strSelect = '';
    $strMessage = '';
   
    
    if(isset($_GET["submit"]))
    {
        $submit = $_GET["submit"];
    }
 
    if($submit == '')
    {
        displayForm();
    }
    else 
    {
        validate();
    }

function validate()
{    
   global $err;
   
   global $strName;
   global $strEmail;
   global $strSelect;
   global $strMessage;
   
   if(isset($_POST["name"]))
   {
       $strName = $_POST["name"];
   }
   
   if(isset($_POST["email"]) && !empty(trim($_POST["email"])))
   {
       $strEmail = $_POST["email"];
   }
   else 
   {
       $err = 1;
   }
   
   if(isset($_POST["selection"]))
   {
       $strSelect = $_POST["selection"];
   }
   else
   { 
       $err = 1;
   }
   
   if(isset($_POST["message"]) && !empty(trim($_POST["message"])))
   {
       $strMessage = $_POST["message"];
   }
   else 
   {
       $err = 1;
   }
   
   if($err = 1)
   {
       displayForm();       
   }
   else
   {
       sendEmail();
   }    
}

Open in new window

0
 
LVL 8

Accepted Solution

by:
Ahmed Merghani earned 500 total points
ID: 40346674
Your code should be changed to something like this:
if(isset($_POST["email"]) && (trim($_POST["email"]) != false))
   {
       $strEmail = $_POST["email"];
   }
   else 
   {
       $err = 1;
   }

Open in new window

Prior to PHP 5.5, empty() only supports variables; anything else will result in a parse error. In other words, the following will not work: empty(trim($name)). Instead, use trim($name) == false.
See this link:
http://us3.php.net/manual/en/function.empty.php
0
 
LVL 109

Expert Comment

by:Ray Paseur
ID: 40346678
As a general rule, compound statements with multiple function calls in the same line of code are a path to confusion.  I believe this statement is causing the problem:

empty(trim($_POST["email"]))

Try something more like this:

$email = trim($_POST['email']);
if (empty($email)) /* DO SOMETHING */

Long ago, PHP allowed this sort of thing, but it's not allowed any more.  That's one of the risks of getting old bits of code from the internet - you don't really know if it works.  Maybe it used to work and doesn't any more.
0

Featured Post

Gigs: Get Your Project Delivered by an Expert

Select from freelancers specializing in everything from database administration to programming, who have proven themselves as experts in their field. Hire the best, collaborate easily, pay securely and get projects done right.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Suggested Solutions

Title # Comments Views Activity
xampp tool 12 48
Why my select dropdown does not work? 8 40
PHP & MySQL - Rounding Results from a Select Query 3 25
PHP curl issue VERBOSE output 18 36
Deprecated and Headed for the Dustbin By now, you have probably heard that some PHP features, while convenient, can also cause PHP security problems.  This article discusses one of those, called register_globals.  It is a thing you do not want.  …
Developers of all skill levels should learn to use current best practices when developing websites. However many developers, new and old, fall into the trap of using deprecated features because this is what so many tutorials and books tell them to u…
The viewer will learn how to dynamically set the form action using jQuery.
The viewer will learn how to count occurrences of each item in an array.

786 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question