Solved

Python - Help - This unexpected EOF error is absurd!

Posted on 2014-09-26
2
347 Views
Last Modified: 2014-09-26
Hi

My code below gives an unexpected EOF error, and it says this error is usually associated with spacing. My indentation seems correct. It says the problem is the last line, bit.

I don't know why . . Thanks
?
import socket

class ClientInfo():
    def __init__(self, ip=None, port=None):
        self.ip = ip
        self.port=port








clients = []


# communication packet codes..

MSG_HELO=1

# byte array conversion methods

def intToBytes(n):
    b = bytearray([0, 0, 0, 0])   # init
    b[3] = n & 0xFF
    n >>= 8
    b[2] = n & 0xFF
    n >>= 8
    b[1] = n & 0xFF
    n >>= 8
    b[0] = n & 0xFF    
    
    # Return the result or as bytearray or as bytes (commented out)
    ##return bytes(b)  # uncomment if you need
    return b
    
    
def bytesToInt(b, offset):
    n = (b[offset+0]<<24) + (b[offset+1]<<16) + (b[offset+2]<<8) + b[offset+3]
    return n


###############################



# create an INET, STREAMing socket
serversocket = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
# bind the socket to a public host, and a well-known port
serversocket.bind((socket.gethostname(), 4321))

# become a server socket

JOIN_BUFFER_SIZE=5
print("listening")
serversocket.listen(5)
waitingForAllClients=True

while waitingForAllClients:
    # accept connections from outside

    print("Deep Red Wars\nServer : Joining Phase . . accept()")
    (clientsocket, address) = serversocket.accept()
    print("TCP joined from : ", address)
    
    print("(TCP recv wait:")
    data = clientsocket.recv(JOIN_BUFFER_SIZE)
    print("TCP received")

    # Analyze msg for joining clients

    print("Msg Type = ")
    print(data[0])

    if data[0] == 1 :
        print("JOIN ")
        clients.append(ClientInfo(address, 8080)

Open in new window

0
Comment
Question by:beavoid
[X]
Welcome to Experts Exchange

Add your voice to the tech community where 5M+ people just like you are talking about what matters.

  • Help others & share knowledge
  • Earn cash & points
  • Learn & ask questions
2 Comments
 
LVL 35

Accepted Solution

by:
Robert Schutt earned 500 total points
ID: 40347175
well, I'm not sure if you posted the full code, but as posted, the last line is missing a closing parenthesis:
clients.append(ClientInfo(address, 8080))

Open in new window

0
 

Author Comment

by:beavoid
ID: 40347199
How humiliating ;)

I haven't made that mistake since before CS100.
J++ IDE parentheses balancing has made me complacent!
Thanks
0

Featured Post

Free Tool: ZipGrep

ZipGrep is a utility that can list and search zip (.war, .ear, .jar, etc) archives for text patterns, without the need to extract the archive's contents.

One of a set of tools we're offering as a way to say thank you for being a part of the community.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Variable is a place holder or reserved memory locations to store any value. Which means whenever we create a variable, indirectly we are reserving some space in the memory. The interpreter assigns or allocates some space in the memory based on the d…
Strings in Python are the set of characters that, once defined, cannot be changed by any other method like replace. Even if we use the replace method it still does not modify the original string that we use, but just copies the string and then modif…
Learn the basics of if, else, and elif statements in Python 2.7. Use "if" statements to test a specified condition.: The structure of an if statement is as follows: (CODE) Use "else" statements to allow the execution of an alternative, if the …
Learn the basics of modules and packages in Python. Every Python file is a module, ending in the suffix: .py: Modules are a collection of functions and variables.: Packages are a collection of modules.: Module functions and variables are accessed us…

726 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question