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remove duplicate line breaks from a txt file using batch file

Hi

My PHP error log files are renamed on a daily basis but they are also full of duplicate carriage returns which I'm currently removing using regex in textpad replacing \n\n with \n

This is my batch file that renames them each day at midnight, how can I incorporate something in it to remove the extra line breaks before saving please?

for /f "tokens=1-5 delims=/ " %%d in ("%date%") do rename "php-errors.log" %%d-%%e-%%f.txt

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Neil Thompson
Asked:
Neil Thompson
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2 Solutions
 
Haris DjulicCommented:
Based on the solution on the link http://www.experts-exchange.com/Programming/Languages/Scripting/Shell/Batch/Q_23027665.html

here is the code which does requested.

@echo off
set source=C:\30092014
set dest=C:\30092014
for /f "tokens=*" %%a in ('dir /b /a-d "%source%\php-errors.log"') do call :process %%a
for /f "tokens=1-5 delims=/ " %%d in ("%date%") do rename "tmp_php-errors.log" %%d-%%e-%%f.txt

goto :eof
 
:process
set filename=%*
echo Working on %filename%
type "%source%\%filename%" > "%source%\tmp_%filename%"
findstr /B /I /R "[!-z]" "%source%\tmp_%filename%" > "%dest%\%filename%"

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QlemoC++ DeveloperCommented:
Using findstr is a neat trick found by Steve (dragon-it), but we can simplify the above code as we are certain there is only one file - no loop needed here.
@echo off
type php-errors.log | findstr /B /I /R "[!-z]" > %date:~0,2%-%date:~3,2%-%date:~6,4%.txt

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or, if you prefer the original date string construction
@echo off
for /f "tokens=1-5 delims=/ " %%d in ("%date%") do set newname=%%d-%%e-%%f.txt
type php-errors.log | findstr /B /I /R "[!-z]" > %newname%.txt

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Neil ThompsonSenior Systems DeveloperAuthor Commented:
Many thanks All,
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