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Open Windows explorer to folder if not already open

Posted on 2014-09-30
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Last Modified: 2014-09-30
I am using the following code to launch Windows explorer to a specified folder. Is there any easy way to test if there is already a window displaying the folder so I don't reopen it?
    Dim sFilePath As String

    On Error GoTo btnOpenFolder_Click_Error
   
    If Dir(PLANPATH & Me.Customer & "\" & Me.JobName, vbDirectory) <> "" Then
        sFilePath = PLANPATH & Me.Customer & "\" & Me.JobName
    Else
        sFilePath = PLANPATH
    End If
   
    On Error Resume Next

    Shell "explorer.exe " & sFilePath, vbNormalFocus

    On Error GoTo 0
    Exit Sub


btnOpenFolder_Click_Error:

    MsgBox Err.Number & " " & Err.Description, , "Error"
0
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Question by:Rob4077
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2 Comments
 
LVL 25

Accepted Solution

by:
chaau earned 500 total points
ID: 40353873
Use ShellExecute Windows API. It is smart enough to not open another explorer if one already opened for the path:

Private Declare Function ShellExecute Lib "shell32.dll" Alias "ShellExecuteA" (ByVal hWnd As Long, ByVal lpOperation As String, ByVal lpFile As String, ByVal lpParameters As String, ByVal lpDirectory As String, ByVal nShowCmd As Long) As Long

Private Sub Command0_Click()
 Dim sFilePath As String

    On Error GoTo btnOpenFolder_Click_Error
   
    sFilePath = "c:\temp"
   
    On Error Resume Next

    'Shell "explorer.exe " & sFilePath, vbNormalFocus
    ShellExecute 0&, vbNullString, sFilePath, vbNullString, vbNullString, vbNormalFocus

    On Error GoTo 0
    Exit Sub


btnOpenFolder_Click_Error:

    MsgBox Err.Number & " " & Err.Description, , "Error"
End Sub

Open in new window

I have changed the sFilePath for testing in the code above
0
 

Author Comment

by:Rob4077
ID: 40353902
That was an easy solution. Thanks!!!!
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