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MYSQL: How to get different columns from different tables using one select statement

Posted on 2014-10-01
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Last Modified: 2014-10-02
I have two very similar tables (with identical column names), that I want to get results from using a single query.

My SQL is this

SELECT mbtd_yield_classic_round1.yldGrowerID, Sum(mbtd_yield_classic_round1.yldYield) AS SumYield1, Sum(mbtd_yield_classic_round2.yldYield) AS SumYield2
FROM mbtd_yield_classic_round1, mbtd_yield_classic_round2
GROUP BY mbtd_yield_classic_round1.yldGrowerID;

Open in new window


However as I am summing the Yield columns, the value returned are not what I expect. They should be:
A : 5.1 : 3.2
B : 3.7 : 4.0

instead I get

A : 51 : 36
A : 37 : 36

Can someone help me please to get the correct results from this simple query ?
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Question by:Sean Clarke
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8 Comments
 
LVL 35

Expert Comment

by:Dan Craciun
ID: 40354931
Can you please provide some sample data?
0
 
LVL 26

Expert Comment

by:Tomas Helgi Johannsson
ID: 40355484
Hi!

You will need to summarize one table at a time and then combine those results into one
like this

SELECT t1.yldGrowerID, Sum(t1.yldYield) AS SumYield
FROM mbtd_yield_classic_round1 t1
GROUP BY t1.yldGrowerID;
UNION
SELECT t2.yldGrowerID, Sum(t2.yldYield) AS SumYield
FROM mbtd_yield_classic_round2 t2 
GROUP BY t2.yldGrowerID;

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Regards,
     Tomas Helgi
0
 
LVL 1

Author Comment

by:Sean Clarke
ID: 40356339
Hi, Sorry - I forgot to post my sample data.

Tomas, this UNION will only give me One Grower ID and ONE TOTAL SUM.
I Need two Totals - one from Table 1 and one from Table 2.
Table-1.PNG
Table-2.PNG
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LVL 35

Accepted Solution

by:
Dan Craciun earned 2000 total points
ID: 40356355
Remove the GROUP By and the SUM and the problem will become apparent: you're using a Cartesian product, which means the resulting table will have 10X10 rows.

Try something like this:
SELECT t3.yldGrowerID, SUM(SumYield1), SUM(SumYield2)
FROM
(SELECT t1.yldGrowerID, Sum(t1.yldYield) AS SumYield1, '0' as SumYield2
FROM mtbd_yield_classic_round1 t1
GROUP BY t1.yldGrowerID
UNION
SELECT t2.yldGrowerID, '0' AS SumYield1, Sum(t2.yldYield) AS SumYield2
FROM mtbd_yield_classic_round2 t2 
GROUP BY t2.yldGrowerID) t3
GROUP BY t3.yldGrowerID

Open in new window

0
 
LVL 26

Expert Comment

by:Tomas Helgi Johannsson
ID: 40356444
Hi!

Then if you use UNION ALL like this
SELECT t1.yldGrowerID, Sum(t1.yldYield) AS SumYield
FROM mbtd_yield_classic_round1 t1
GROUP BY t1.yldGrowerID;
UNION ALL
SELECT t2.yldGrowerID, Sum(t2.yldYield) AS SumYield
FROM mbtd_yield_classic_round2 t2 
GROUP BY t2.yldGrowerID;

Open in new window


You should get 2 rows and if they are identical then the sum and values for yldGrowerID are the same in both
tables.

Regards,
    Tomas Helgi
0
 
LVL 35

Expert Comment

by:Dan Craciun
ID: 40356480
@Tomas: the OP wants the result to have 2 rows and 3 columns:

yldGrowerID  |  SumYield1  | SumYield2
     A                 |         5.1        |     3.2
     B                 |         3.7        |     4.0

Your query returns 4 rows and 2 columns.
0
 
LVL 1

Author Closing Comment

by:Sean Clarke
ID: 40356652
Excellent thank for this - kind of obvious when I look at what you've done, but would have never worked it out on my own.

My final query ended up like this:

SELECT t3.yldGrowerID, ROUND(SUM(t3.SumYield1),2) AS SumYield1, ROUND(SUM(t3.SumYield2),2) AS SumYield2 FROM
(SELECT t1.yldGrowerID, SUM(t1.yldYield) AS SumYield1, '0' AS SumYield2 FROM mbtd_yield_classic_round1 t1 GROUP BY t1.yldGrowerID
UNION
SELECT t2.yldGrowerID, '0' AS SumYield1, SUM(t2.yldYield) AS SumYield2 FROM mbtd_yield_classic_round2 t2 GROUP BY t2.yldGrowerID) t3 GROUP BY t3.yldGrowerID
0
 
LVL 35

Expert Comment

by:Dan Craciun
ID: 40356683
Glad I could help!
0

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