JeffBeall
asked on
subnetting
I'm studying for the Network + test, and for subnetting, I don't have a problem subnetting class C networks, but I'm confused on class B.
the method the book I'm using is to ask 5 questions
how many subnets - the formula is 2 to the X power - x = number of masked bits - no problems there
how many hosts per subnet - formula is 2 to the Y power minus 2 y = number of host per subnet
what art the valid subnets formula is 265 - subnet mask = block size aka increment number - now this is what throws me,
so, for example, if i have a class B network and the mask is 255.255.240.0 (/20) i would use the formula
256-240 = 16 so the block size or increment number is 16. in the book, he makes a chart like this
subnet 0.0 16.0 32.0 48.0
first host 0.1 16.1 32.1 48.1
last host 15.254 31.254 47.254 63.254
broadcast 15.255 31.255 47.255 63.255
so does this mean that in the first column for instance. if the address is 172.16.X.Y the first host address is 172.16.0.1 and the last address in subnet 0.0 is 172.16.15.254? which means there are LOTS of hosts?
the method the book I'm using is to ask 5 questions
how many subnets - the formula is 2 to the X power - x = number of masked bits - no problems there
how many hosts per subnet - formula is 2 to the Y power minus 2 y = number of host per subnet
what art the valid subnets formula is 265 - subnet mask = block size aka increment number - now this is what throws me,
so, for example, if i have a class B network and the mask is 255.255.240.0 (/20) i would use the formula
256-240 = 16 so the block size or increment number is 16. in the book, he makes a chart like this
subnet 0.0 16.0 32.0 48.0
first host 0.1 16.1 32.1 48.1
last host 15.254 31.254 47.254 63.254
broadcast 15.255 31.255 47.255 63.255
so does this mean that in the first column for instance. if the address is 172.16.X.Y the first host address is 172.16.0.1 and the last address in subnet 0.0 is 172.16.15.254? which means there are LOTS of hosts?
ASKER CERTIFIED SOLUTION
membership
This solution is only available to members.
To access this solution, you must be a member of Experts Exchange.
SOLUTION
membership
This solution is only available to members.
To access this solution, you must be a member of Experts Exchange.
SOLUTION
membership
This solution is only available to members.
To access this solution, you must be a member of Experts Exchange.
ASKER