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# substring example to delte string

Posted on 2014-10-04
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Hi

I am trying below challenge

http://codingbat.com/prob/p100905

I wrote as below

public String delDel(String str) {
if((str.substring(1)).equals("del")){
return str-"del";
}
return str;
}

what is the best way to see 'del' is there in given string and delete from exact same location. Please advise
0
Question by:gudii9
• 11
• 4
• 4
• +2

LVL 84

Assisted Solution

ozo earned 100 total points
return str.replaceFirst("(?<=^.)del","");
0

LVL 26

Accepted Solution

dpearson earned 100 total points
You can't use the "-" operator to remove the string.

But you can build up the string with a piece missing like this:
return str.substring(0, pos) + str.substring(pos+3) ;
which returns the string to position 'pos', plus the string from 'pos+3' to the end - which means the string but with 3 characters removed at position 'pos'.

Using that you can do this:

public String delDel(String str) {
int pos = str.indexOf("del") ;
if (pos == -1 || pos != 1)
return str ;
return str.substring(0, pos) + str.substring(pos+3) ;
}
0

LVL 7

Author Comment

?<=^.

what is meaning of above code.

Is it is some kind of regular expression. Please advise
0

LVL 27

Assisted Solution

rrz earned 100 total points
First let's explain your errors.
``````if((str.substring(1)).equals("del")){
``````
This won't work because str.substring(1) is the entire String minus the first character.
``````return str-"del";
``````
This won't work because you can't use the - operator in that way. You can use the + operator for concatenating Strings. But you can't subtract with - operator.  ozo's solution is good.  But, the following is easier to understand.
``````public String delDel(String str) {
if(str.length()>3 && (str.substring(1,4)).equals("del")){
return str.replaceFirst("del","");
}
return str;
}
``````
0

LVL 27

Expert Comment

Using dpearson's and ozo's ideas, here is another solution.
``````public String delDel(String str) {
if(str.indexOf("del") == 1){
return str.replaceFirst("del","");
}
return str;
}
``````
0

LVL 86

Assisted Solution

CEHJ earned 200 total points
Another way:
``````public String delDel(String str) {
StringBuilder sb = new StringBuilder(str);
int ixDel = sb.indexOf("del");
return ixDel == 1? sb.delete(ixDel, 4).toString() : str;
}
``````
0

LVL 84

Expert Comment

Or, if you want to avoid calling StringBuilder unnecessarily:
return str.indexOf("del") == 1? new StringBuilder(str).delete(1, 4).toString() : str;
0

LVL 86

Expert Comment

He he - good one ;)
0

LVL 7

Author Comment

if (pos == -1 || pos != 1)

why are we checking pos is not equal to 1 as above. Please advise
0

LVL 7

Author Comment

`````` return str.indexOf("del") == 1? new StringBuilder(str).delete(1, 4).toString() : str;
``````

why are we checking indexOf("del") is 1 or not as above then if it then delete(1,4). Otherwise return same string

0

LVL 7

Author Comment

``````return ixDel == 1? sb.delete(ixDel, 4).toString() : str;
``````

why we have given 4 as argument of delete method. I thought it should have been 3.

All the test cases passed as below

``````public String delDel(String str) {
StringBuilder sb = new StringBuilder(str);
int ixDel = sb.indexOf("del");
return ixDel == 1? sb.delete(ixDel, 4).toString() : str;
}
``````

Expected      Run
delDel("adelbc") â†’ "abc"      "abc"      OK
delDel("adelHello") â†’ "aHello"      "aHello"      OK
delDel("abcdel") â†’ "abcdel"      "abcdel"      OK
delDel("a") â†’ "a"      "a"      OK
delDel("") â†’ ""      ""      OK
delDel("del") â†’ "del"      "del"      OK
delDel("adel") â†’ "a"      "a"      OK
0

LVL 7

Author Comment

``````str.replaceFirst("del","");
``````

I was checking the API
http://docs.oracle.com/javase/7/docs/api/java/lang/String.html

I wonder why there is no replaceLast method similar to replaceFirst.
0

LVL 26

Expert Comment

if (pos == -1 || pos != 1)
why are we checking pos is not equal to 1 as above. Please advise

The problem said "if the string "del" appears starting at index 1" so checking if (pos != 1) is checking for whether the string is at index 1.

Looking at this I realize I made it more complex than it needs to be because of course if "pos == -1" then that means "pos != 1" is true, so we can just write this as:

if (pos != 1) ...

I wonder why there is no replaceLast method similar to replaceFirst.
This is just because the people who wrote Java (Sun) thought that it would be more common for people to want to replace the first string that matches a pattern rather than the last string.  When designing classes and methods there's a lot of asking "how will people most often want to use this" and that shows up in the design.  They certainly could have added a "replaceLast" method.  They just didn't think it would be used that often.

Doug
0

LVL 86

Expert Comment

why are we checking indexOf("del") is 1 or not as above then if it then delete(1,4). Otherwise return same string

Because that is what's specified
0

LVL 7

Author Comment

return str.replaceFirst("(?<=^.)del","");

what is meaning of ?<=^.

0

LVL 7

Author Comment

I checked api

String      replaceFirst(String regex, String replacement)
Replaces the first substring of this string that matches the given regular expression with the given replacement

It did not talk about ?<=^.

0

LVL 84

Expert Comment

0

LVL 7

Author Comment

i need to read it more
0

LVL 27

Expert Comment

To explain (?<=^.)del
http://www.regular-expressions.info/lookaround.html
0

LVL 7

Author Comment

public String delDel(String str) {
StringBuilder sb = new StringBuilder(str);
int ixDel = sb.indexOf("del");
return ixDel == 1? sb.delete(ixDel, 4).toString() : str;
}

As above it is all working fine.
Below line

return ixDel == 1? sb.delete(ixDel, 4).toString() : str;

why we have given 4 as argument of delete method. I thought it should have been 3.
0

LVL 27

Expert Comment

Look at the API
http://docs.oracle.com/javase/7/docs/api/java/lang/StringBuilder.html#delete(int,%20int)
it says
end - The ending index, exclusive.
Therefore the end index is excluded from the delete.
So, if we want to delete "del" at index 1,2,3,  then we should use 4 for end
0

LVL 26

Expert Comment

Yeah - the key part as rrz mentioned is that the "end index" does NOT include that position.

This is true for all of the string operations.

So delete(0,1) means "delete the character starting at position 0 and ending BEFORE position 1" - so just 1 character at position 0.

etc.

Doug
0

LVL 7

Author Comment

replace
public StringBuilder replace(int start,
int end,
String str)
Replaces the characters in a substring of this sequence with characters in the specified String. The substring begins at the specified start and extends to the character at index end - 1 or to the end of the sequence if no such character exists. First the characters in the substring are removed and then the specified String is inserted at start. (This sequence will be lengthened to accommodate the specified String if necessary.)
Parameters:
start - The beginning index, inclusive.
end - The ending index, exclusive.
str - String that will replace previous contents.
Returns:
This object.
Throws:
StringIndexOutOfBoundsException - if start is negative, greater than length(), or greater than end.

I see replace function also has end exclusive.

What other functions of String has end as exclusive apart from delete, replace. please advise
0

LVL 26

Expert Comment

Any string function that takes a range (e.g. substring) always has the end index being exclusive.

It would be very confusing if some of them weren't.  They're all the same.
0

LVL 7

Author Comment

StringBuilder      delete(int start, int end)
Removes the characters in a substring of this sequence.

I see one other in StringBuilder with end exclusive
0

LVL 86

Assisted Solution

CEHJ earned 200 total points
I see one other in StringBuilder with end exclusive
That's the point - the end is exclusive
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