sql server 2008 - Derived Table SUM (Aggregate)

Hello Experts,
Can you please look at this and give me a solution. I don't want to change this format of the derived table as I have tons created same way but want to aggregate result of both sums like this
SUM ( A1.CM_Sales + B1.YTD_Sales) AS 'Total Sales'  -> I want to sum result of both the derived tables


SELECT a1.Sto_Name,
       CM_Count,
       CM_Sales,
       YTD_Count,
       YTD_Sales
FROM (SELECT b.Sto_Name,
             COUNT(*) AS CM_Count,
             SUM(Sal_Amt) AS CM_Sales
      FROM Sales a
      JOIN Stores b ON a.Sto_ID = b.Sto_ID
      WHERE DATEPART(yy,Sal_Date) = DATEPART(yy,@RunDate) AND
            DATEPART(mm,Sal_Date) = (DATEPART(mm,@RunDate)-1)
      GROUP BY b.Sto_Name) AS A1

JOIN (SELECT Sto_Name,
             COUNT(*) AS YTD_Count,
             SUM(Sal_Amt) AS YTD_Sales
      FROM Sales a
      JOIN Stores b ON a.Sto_ID = b.Sto_ID
      WHERE DATEPART(yy,Sal_Date) = DATEPART(yy,@RunDate)
      GROUP BY b.Sto_Name) AS B1  ON a1.Sto_Name = b1.Sto_Name
BI 0824Asked:
Who is Participating?
I wear a lot of hats...

"The solutions and answers provided on Experts Exchange have been extremely helpful to me over the last few years. I wear a lot of hats - Developer, Database Administrator, Help Desk, etc., so I know a lot of things but not a lot about one thing. Experts Exchange gives me answers from people who do know a lot about one thing, in a easy to use platform." -Todd S.

PortletPaulfreelancerCommented:
Are you sure you want to add the Year To Date with Current Month? (normally YTD already includes CM)

That could double count the current month.

Are you certain DATEPART(mm,Sal_Date) = (DATEPART(mm,@RunDate)-1) will always work correctly?
(what happens if @RunDate is in Januarury?)

And, are you sure you don't want to simplify, e.g.

SELECT
      Sto_Name
    , COUNT(CASE WHEN DATEPART(mm, Sal_Date) = (DATEPART(mm, @RunDate) - 1) THEN a.Sto_ID_ID END)  AS CM_Count
    , SUM(CASE WHEN DATEPART(mm, Sal_Date) = (DATEPART(mm, @RunDate) - 1) THEN Sal_Amt ELSE 0 END) AS CM_Sales
    , COUNT(*)                                                                                     AS YTD_Count
    , SUM(Sal_Amt)                                                                                 AS YTD_Sales
FROM Sales a
      JOIN Stores b
                  ON a.Sto_ID = b.Sto_ID
WHERE DATEPART(yy, Sal_Date) = DATEPART(yy, @RunDate)
GROUP BY
      b.Sto_Name
;

Open in new window

0
BI 0824Author Commented:
The one given is not mine I mean the query but all the queries I need to deal with r the same like example given. So I just need to know how to sum both the values in the given format
0
PortletPaulfreelancerCommented:
Whether they are yours or not isn't the issue - if you add those 2 numbers together the result will be wrong

The existing query will not work in January either.

Are you really determined to get a query that gives you bad results?

Here is how you would add those 2 numbers together:
All you need to do is place the calculation into the select clause, but you don't need SUM()

SELECT a1.Sto_Name,
       CM_Count,
       CM_Sales,
       YTD_Count,
       YTD_Sales,
       A1.CM_Sales + B1.YTD_Sales AS 'Total Sales' --<< BUT THIS IS A BAD NUMBER
FROM (
0

Experts Exchange Solution brought to you by

Your issues matter to us.

Facing a tech roadblock? Get the help and guidance you need from experienced professionals who care. Ask your question anytime, anywhere, with no hassle.

Start your 7-day free trial
BI 0824Author Commented:
Sorry about the late reply. It worked for me the way you did. Thanks.
0
It's more than this solution.Get answers and train to solve all your tech problems - anytime, anywhere.Try it for free Edge Out The Competitionfor your dream job with proven skills and certifications.Get started today Stand Outas the employee with proven skills.Start learning today for free Move Your Career Forwardwith certification training in the latest technologies.Start your trial today
Microsoft SQL Server

From novice to tech pro — start learning today.

Question has a verified solution.

Are you are experiencing a similar issue? Get a personalized answer when you ask a related question.

Have a better answer? Share it in a comment.