SQL query to sub-total data

I have a very basic understanding of SQL and need to modify a query which someone else created.  The current query shows the number of clients added to our database within a time window.  We now want to sub-total this query by branch, by quarter.

The current query is this:

declare     @start_date datetime

      select      @start_date = dateadd(mm,-24,getdate())

      select
            @start_date                       as period_desc,
            office_name,
            c.client_org_name                 as parent_company,
            a.client_org_name                 as company,
            a.address1                        as address1,
            a.address2                        as address2,
            a.city                            as city,
            a.pincode                         as pincode,
            a.state                           as state,
            a.contact_first_name              as contact_first_name,
            a.contact_last_name               as contact_last_name,
            a.contact_phone                   as contact_phone,
            a.client_id                       as client_id,
            a.created_on                      as created_on,
            isnull(count(d.group_id),0)         as number_of_orders

      from  client_organization     a,
            branch_offices           b,
            client_organization     c,
            orders                  d

      where b.office_id =  a.office_id
      and   c.group_id  =  a.client_id
      and   d.group_id  =* a.group_id
      and   a.created_on >= @start_date

      group by office_name, c.client_org_name, a.client_org_name, a.address1, a.address2, a.city, a.pincode, a.state,
             a.contact_first_name, a.contact_last_name, a.contact_phone, a.client_id, a.created_on

      order by office_name, parent_company, company


Can anyone assist in breaking the details down to sub-total this, as requested.

Any assistance is appreciated.
DrakeCAAsked:
Who is Participating?
I wear a lot of hats...

"The solutions and answers provided on Experts Exchange have been extremely helpful to me over the last few years. I wear a lot of hats - Developer, Database Administrator, Help Desk, etc., so I know a lot of things but not a lot about one thing. Experts Exchange gives me answers from people who do know a lot about one thing, in a easy to use platform." -Todd S.

Vitor MontalvãoMSSQL Senior EngineerCommented:
If the field CREATEDON is date data type than this should work:
declare     @start_date datetime

select      @start_date = dateadd(mm,-24,getdate())

select
     @start_date                       as period_desc,
     office_name,
     c.client_org_name                 as parent_company,
     a.client_org_name                 as company,
     a.address1                        as address1,
     a.address2                        as address2,
     a.city                            as city,
     a.pincode                         as pincode,
     a.state                           as state,
     a.contact_first_name              as contact_first_name,
     a.contact_last_name               as contact_last_name,
     a.contact_phone                   as contact_phone,
     a.client_id                       as client_id,
     DATEPART (QUARTER, a.created_on)  as created_on,
     isnull(count(d.group_id),0)       as number_of_orders
from  client_organization     a,
     branch_offices           b,
     client_organization     c,
     orders                  d
where b.office_id =  a.office_id
and   c.group_id  =  a.client_id
and   d.group_id  =* a.group_id
and   a.created_on >= @start_date
group by office_name, c.client_org_name, a.client_org_name, a.address1, a.address2, a.city, a.pincode, a.state,
      a.contact_first_name, a.contact_last_name, a.contact_phone, a.client_id
order by office_name, parent_company, company

Open in new window

0
DrakeCAAuthor Commented:
This tells me the quarter the order was created on, but doesn't provide any sub-totals per branch, per quarter.

How do I get that additional information?
0
Vitor MontalvãoMSSQL Senior EngineerCommented:
Do you need to present all those columns? If not you can reduce It only to those one that really matters. Like this:
declare     @start_date datetime

select      @start_date = dateadd(mm,-24,getdate())

select
     @start_date                       as period_desc,
     office_name,
     DATEPART (QUARTER, a.created_on)  as created_on,
     isnull(count(d.group_id),0)       as number_of_orders
from  client_organization     a,
     branch_offices           b,
     client_organization     c,
     orders                  d
where b.office_id =  a.office_id
and   c.group_id  =  a.client_id
and   d.group_id  =* a.group_id
and   a.created_on >= @start_date
group by office_name
order by office_name

Open in new window

0
Ultimate Tool Kit for Technology Solution Provider

Broken down into practical pointers and step-by-step instructions, the IT Service Excellence Tool Kit delivers expert advice for technology solution providers. Get your free copy now.

DrakeCAAuthor Commented:
Sure, we can minimize the report to only those fields, just to pull this particular information.

How would I subtotal it by branch, per quarter then?
0
Vitor MontalvãoMSSQL Senior EngineerCommented:
Isn't the number of orders that you want (it's the last column in the SELECT fields)?
If not just replace it for the field that you want. And the operation also (COUNT or SUM)?
declare     @start_date datetime

select      @start_date = dateadd(mm,-24,getdate())

select
     @start_date                       as period_desc,
     office_name,
     DATEPART (QUARTER, a.created_on)  as created_on,
     count(d.group_id)       as number_of_orders
from  client_organization     a,
     branch_offices           b,
     client_organization     c,
     orders                  d
where b.office_id =  a.office_id
and   c.group_id  =  a.client_id
and   d.group_id  =* a.group_id
and   a.created_on >= @start_date
group by office_name
order by office_name

Open in new window

0
DrakeCAAuthor Commented:
I'm not looking for the total number of orders.  I'm trying to determine the total number of clients added to the system.  Technically every client should have a unique ID number.  I assume I would count based on that ID number?

When I post the query you have listed I get an error stating "Msg 8120, Level 16, State 1, Line 5
Column 'client_organization.created_on' is invalid in the select list because it is not contained in either an aggregate function or the GROUP BY clause."


How do I get rid of that error?  I tried adding "created_on" to the group_by line, but it tells me it's an ambiguous column name.
0
Vitor MontalvãoMSSQL Senior EngineerCommented:
Ok. Now we have something. Try this one:
declare     @start_date datetime

select      @start_date = dateadd(mm,-24,getdate())

select
     @start_date                       as period_desc,
     office_name,
     DATEPART (QUARTER, a.created_on)  as created_on,
     count(a.client_id)       as number_of_clients
from  client_organization     a,
     branch_offices           b,
     client_organization     c,
     orders                  d
where b.office_id =  a.office_id
and   c.group_id  =  a.client_id
and   d.group_id  =* a.group_id
and   a.created_on >= @start_date
group by office_name, DATEPART (QUARTER, a.created_on)
order by office_name

Open in new window

0
DrakeCAAuthor Commented:
I ended up using the query below:

use olo_na

declare     @start_date datetime
select      @start_date = dateadd(mm,-24,getdate())

SELECT office_name, DATEPART(YEAR,a.created_on) [Year],
DATEPART(QUARTER,a.created_on) [Quarter],
COUNT(1) [created_on]
FROM client_organization a
left join branch_offices  b on b.office_id =  a.office_id
where a.created_on >= @start_date
GROUP BY office_name, DATEPART(YEAR,a.created_on),DATEPART(QUARTER,a.created_on)
ORDER BY 1,2,3
0

Experts Exchange Solution brought to you by

Your issues matter to us.

Facing a tech roadblock? Get the help and guidance you need from experienced professionals who care. Ask your question anytime, anywhere, with no hassle.

Start your 7-day free trial
Vitor MontalvãoMSSQL Senior EngineerCommented:
Even I didn't give you the solution, maybe for lack of information from you, your solution was based on mine.
0
DrakeCAAuthor Commented:
This is the solution
0
It's more than this solution.Get answers and train to solve all your tech problems - anytime, anywhere.Try it for free Edge Out The Competitionfor your dream job with proven skills and certifications.Get started today Stand Outas the employee with proven skills.Start learning today for free Move Your Career Forwardwith certification training in the latest technologies.Start your trial today
Microsoft SQL Server

From novice to tech pro — start learning today.

Question has a verified solution.

Are you are experiencing a similar issue? Get a personalized answer when you ask a related question.

Have a better answer? Share it in a comment.