My PowerPivot formula works on individual components but combination gives error

I try to create a formula in Power Pivot, where I try to generate a new column (or even better a measure if anybody can help on that

=mid([Placement],11,1) returns correctly the 11th character, if the [Placement] column has characters
=if(len([Placement])>0,1,2) returns correctly either 1 or 2 dependent on the length of [Placement]

But combining the two into one new Column like below generates an error

=if(len([Placement])>0,mid([Placement],11,1),2)

Urgent help is needed.

best regards

Jørgen
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JorgenConsultantAsked:
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Rory ArchibaldCommented:
Shouldn't your formula be:
=if(len([Placement])>10,mid([Placement],11,1),2)

I don't see how that could be a measure - it doesn't really make sense to me.
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JorgenConsultantAuthor Commented:
Hi Rory,

Most of the Placement records are actually blank, which is the reason for selecting 0. and I tried the measure part as well, and it did not make sense for me either. But I thought it was my lack of knowledge on the measures.

I will check if inserting 10 makes a difference, but I imagine it does not. Do you find any errors in the formula apart from the 10 figure?

best regards

Jørgen
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JorgenConsultantAuthor Commented:
#ERR
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Rory ArchibaldCommented:
If you have any records that are less than 11 characters, you'd get an error, which is why I suggested changing to > 10.
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Rory ArchibaldCommented:
Oh wait - will the 11th character always be a number? If so, use:
=if(len([Placement])>10,mid([Placement],11,1)+0,2)
If not, use:
=if(len([Placement])>10,mid([Placement],11,1),"2")

You can't have different data types returned by the two result arguments.
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JorgenConsultantAuthor Commented:
But I did not get the error on testing
=if(len([Placement])>0,1,2)
and I do also get an error using 10 - no difference at all :-(
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Rory ArchibaldCommented:
See my last post. :)
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JorgenConsultantAuthor Commented:
Hi Rory
Worked like a charm, when I inserted the +0.

Do you by any chance have any experience on the average ytd functionality in Power Pivot (in that case I will post another question)?

best regards

Jørgen
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JorgenConsultantAuthor Commented:
Great solution - and worth to remember in the future
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Rory ArchibaldCommented:
I can't say I've ever used it but feel free to post it and I'm sure we can figure it out. :)
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