What's wrong with this code I'm using to create a csv file?

Here's my code:

$don="SELECT * FROM verizon_data where posted_day='2013-08-06' limit 400000";
$don_query=mysqli_query($cxn, $don);
	if(!$don_query)
	{
	$nuts=mysqli_errno($cxn).': '.mysqli_error($cxn);
	die($nuts);
	}
$don_count=mysqli_num_rows($don_query);
echo $don_count; 

$row=mysqli_fetch_array($don_query, MYSQLI_ASSOC);
	$fp = fopen('file.csv', 'w');

		foreach ($row as $val) {
			fputcsv($fp, $val);
		}

		fclose($fp);

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The error I'm getting says "Warning: fputcsv() expects parameter 2 to be array, string given in C:\wamp\www\json\sandbox.php on line 20"

Line 20 is actually fputcsv($fp, $val)

$val, I'm assuing is the $row and, my first thought was that there was no data. Nope. Plenty of data, so I'm blowing it somewhere but don't know where.

What am I doing wrong?
brucegustPHP DeveloperAsked:
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Ray PaseurCommented:
With MySQLi, we use a while() iterator to retrieve the rows of the results set.  Each row can be retrieved in the form of an array, suitable for use with fputcsv().

The correct design pattern is in the code snippet here, at line #144
http://www.experts-exchange.com/Programming/Languages/Scripting/PHP/Q_28533249.html#a40368499
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brucegustPHP DeveloperAuthor Commented:
Got it working, Ray!

Thanks!

BTW: Some low hanging fruit for if you're willing: http://www.experts-exchange.com/Programming/Languages/Scripting/PHP/Q_28533765.html

Thanks, again!
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Lukasz ChmielewskiCommented:
Maybe you need to fputcsv (without a loop)
fputcsv($fp, $row);

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... edit: too late :)
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