# Display Percentage of total for each record using TSQL

Hello Experts,

I have the following table:

Type      Sum_A      Sum_B
A                  15                16
B                    5                  7
C                    6                  8
D                    0                49

The total for Sum_A = 26
The total for Sum_B = 80

I would like to create a view that displays the % of each Sum_A and Sum_B record to the totals of Sum_A and Sum_B.
It should like this below:

Type      Sum_A      %Tot_A      Sum_B      %Tot_B
A                 15       58%          16                20%
B                   5       19%           7                  9%
C                   6         23%          8                10%
D                   0         0%          49                 61%

For example:
The %Tot_A (for Type A) = 15/26 = 58%
The %Tot_A (for Type B) = 5/26 = 19%
The %Tot_A (for Type C) = 6/26 = 23%
The %Tot_A (for Type D) = 0/26 = 0%

Same for %Tot_B...
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Director, Practice Manager and Computing ConsultantCommented:
Use the following:

SUM_A / Sum(SUM_A) OVER()
0
MSSQL Senior EngineerCommented:
You can use a common table expression here (CTE):
``````CREATE VIEW vPercent AS
WITH Total_CTE (TotalA, TotalB)
AS (SELECT SUM(Sum_A)*1.0, SUM(Sum_B)*1.0
FROM YourTableNameHere)
SELECT A.Type, Sum_A, 100*A.Sum_A/(SELECT Sum_A FROM Total_CTE) AS '%Tot_A',
Sum_B, 100*A.Sum_B/(SELECT Sum_B FROM Total_CTE) AS '%Tot_B',
FROM YourTableNameHere
``````
0
freelancerCommented:
``````| TYPE | SUM_A | %TOT_A | SUM_B | %TOT_B |
|------|-------|--------|-------|--------|
|    A |    15 |  57.69 |    16 |     20 |
|    B |     5 |  19.23 |     7 |   8.75 |
|    C |     6 |  23.08 |     8 |     10 |
|    D |     0 |      0 |    49 |  61.25 |
``````

``````select
type
, sum_a
, round( (sum_a * 100.0) / sum(sum_a) over() ,2) "%Tot_A"
, sum_b
, round( (sum_b * 100.0) / sum(sum_b) over() ,2) "%Tot_B"
from table1
``````
0

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Commented:
This can be done using window functions in sql server.

CREATE TABLE TEST_TYPE (Type   VARCHAR(10),     Sum_A  INT,      Sum_B  INT)
INSERT INTO TEST_TYPE VALUES('A',15,16),('B',5,7),('C',6,8),('D',0,49)

SELECT TYPE
, SUM_A,  CONVERT(VARCHAR,CONVERT(DECIMAL(5,1),100.0 * SUM_A / SUM(sum_a) OVER())) as Percent_A
, SUM_B, CONVERT(VARCHAR,CONVERT(DECIMAL(5,1),100.0 *SUM_B/SUM(sum_b) OVER())) AS Percent_B
FROM TEST_TYPE;

TYPE      SUM_A      Percent_A      SUM_B      Percent_B
A      15      57.7      16      20.0
B      5      19.2      7      8.8
C      6      23.1      8      10.0
D      0      0.0      49      61.3
0
Author Commented:
This works great - Thanks!
0
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Microsoft SQL Server 2005

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