Solved

SQL help needed

Posted on 2014-10-10
15
141 Views
Last Modified: 2014-10-10
Hi Experts

I have a rather complicated stored proc that does take a few seconds to run, it loads customer data from several sources into a temp table, and returns that table.

What I need now is a way to mark customers that have the same name but different ID's so the users can perform additional checks to make sure they have the right one.

I can't think of an efficient way to do this. Maybe a count on name in the temp table?

Andy
0
Comment
Question by:Andy Green
  • 9
  • 5
15 Comments
 
LVL 24

Expert Comment

by:Phillip Burton
ID: 40372623
Use the HAVING clause.
0
 
LVL 24

Expert Comment

by:Phillip Burton
ID: 40372635
Here's my code:

drop table Customers
go

create table Customers
(ID int,
Name varchar(50),
Warning bit null)
go

insert into Customers(ID, Name)
values (1, 'FirstName'), (2, 'SecondName'), (3, 'ThirdName'), (4, 'FirstName')
go

update Customers
set Warning = 0
from Customers
go

with RowsToUpdate as
(select Name, Warning
From Customers
group by Name, Warning
having Count(ID)>1)

update Customers
set Warning = 1
from Customers 
inner join RowsToUpdate 
on Customers.Name = RowsToUpdate.Name

select * from Customers

Open in new window

0
 
LVL 48

Expert Comment

by:PortletPaul
ID: 40372644
Not sure what the field is that you are evaluating, but assuming it's [CUSTOMER_ID] then you would want DISTINCT in the evaluation I think. e.g.

HAVING COUNT(DISTINCT [CUSTOMER_ID]) > 1

e.g.
select *
from staging 
where customer in (
          select Customer
          from staging
          group by Customer
          HAVING COUNT(DISTINCT [CUSTOMER_ID]) > 1
          )

Open in new window

0
Three Reasons Why Backup is Strategic

Backup is strategic to your business because your data is strategic to your business. Without backup, your business will fail. This white paper explains why it is vital for you to design and immediately execute a backup strategy to protect 100 percent of your data.

 
LVL 3

Author Comment

by:Andy Green
ID: 40372748
Its just customer name, its to identify the same name but different ID.

Trying your solution Phillip. Thanks

Andy
0
 
LVL 3

Author Comment

by:Andy Green
ID: 40372886
Phillip I'm using a table variable for my temp table, and The sample you supplied works fine as you have it but not with a table variable,

Declare @Customers table
(ID int,
Name varchar(50),
Warning bit null)

Andy
0
 
LVL 3

Author Comment

by:Andy Green
ID: 40372898
ALso Its not a limited list I need rather as Phillip has done it all the rows with a flag if the name exists in another record.

Andy
0
 
LVL 24

Accepted Solution

by:
Phillip Burton earned 500 total points
ID: 40372901
It does work - you need to get rid of the GO statements and alias the tables.

declare @Customers as table
(ID int,
Name varchar(50),
Warning bit null)

insert into @Customers(ID, Name)
values (1, 'FirstName'), (2, 'SecondName'), (3, 'ThirdName'), (4, 'FirstName')

update @Customers
set Warning = 0
from Customers;


with RowsToUpdate as
(select Name, Warning
From @Customers
group by Name, Warning
having Count(ID)>1)

update @Customers
set Warning = 1
from @Customers C
inner join RowsToUpdate R
on C.Name = R.Name

select * from @Customers

Open in new window

0
 
LVL 3

Author Comment

by:Andy Green
ID: 40372927
I did but it looks like you have to alias the table as you have done.

Andy
0
 
LVL 3

Author Comment

by:Andy Green
ID: 40373212
Nearly there, just struggling on one last point,  It is possible that the same Customer could appear in the list 2 or 3 times, I don't want these highlighted, just those with different ID'd  but the same names.

This is in Wales where same names can be common.

Andy
0
 
LVL 24

Expert Comment

by:Phillip Burton
ID: 40373218
Change the line

having Count(ID)>1)

to

having Count(DISTINCT ID)>1)
0
 
LVL 3

Author Comment

by:Andy Green
ID: 40373246
Sorry still not right:

In this an expanded version of your original code I don't want 4 FirstName to have a warning:

declare @Customers as table
(ID int,
Name varchar(50),
Warning bit null)

insert into @Customers(ID, Name)
values (1, 'FirstName'), (2, 'SecondName'), (3, 'ThirdName'), (4, 'FirstName'), (1, 'FirstName')

update @Customers
set Warning = 0
from @Customers;


with RowsToUpdate as
(select Name, Warning
From @Customers
group by Name, Warning
having Count(Distinct ID)>1)

update @Customers
set Warning = 1
from @Customers C
inner join RowsToUpdate R
on C.Name = R.Name

select * from @Customers
0
 
LVL 3

Author Comment

by:Andy Green
ID: 40373249
Hang on ignore that - I'm getting confused now.

Andy
0
 
LVL 3

Author Comment

by:Andy Green
ID: 40373254
Sorry Phillip, you are right.  Worked fine with Distinct.

Andy
0
 
LVL 3

Author Closing Comment

by:Andy Green
ID: 40373258
Excellent - Thank you.

Andy
0
 
LVL 24

Expert Comment

by:Phillip Burton
ID: 40373259
You may perhaps want to change the very final line to

select distinct * from @Customers
0

Featured Post

Use Case: Protecting a Hybrid Cloud Infrastructure

Microsoft Azure is rapidly becoming the norm in dynamic IT environments. This document describes the challenges that organizations face when protecting data in a hybrid cloud IT environment and presents a use case to demonstrate how Acronis Backup protects all data.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Introduction SQL Server Integration Services can read XML files, that’s known by every BI developer.  (If you didn’t, don’t worry, I’m aiming this article at newcomers as well.) But how far can you go?  When does the XML Source component become …
The Delta outage: 650 cancelled flights, more than 1200 delayed flights, thousands of frustrated customers, tens of millions of dollars in damages – plus untold reputational damage to one of the world’s most trusted airlines. All due to a catastroph…
Via a live example, show how to set up a backup for SQL Server using a Maintenance Plan and how to schedule the job into SQL Server Agent.
Viewers will learn how to use the SELECT statement in SQL to return specific rows and columns, with various degrees of sorting and limits in place.

791 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question