10774: unique combination for c1 and c2

Hello experts:

for each unique combination of materialreal codigocliente and I must add a column with the same number

  SELECT
         [organizacionVenta]
      ,[codigoCliente]
      ,[1-SPOT 2-NSPOT]
      ,[codigoCentro]
      ,[1-Exp 2-Fil 3-Int 4-Loc]
      ,[materialReal]
        ,1 IdAnioEjercicio
  FROM [BPS_STAGE].[dbo].[Copia de Base PG]
  order by  codigoCliente,materialReal  desc

organizacionVenta	codigoCliente	1-SPOT 2-NSPOT	codigoCentro	1-Exp 2-Fil 3-Int 4-Loc	materialReal	IdAnioEjercicio
PE10	100001	2	1000	4	005000090000080324	1
PE10	100001	2	1000	4	005000090000080324	1
PE10	100001	2	1000	4	005000090000080324	1
PE10	100001	2	1000	4	005000090000080324	1
PE10	100001	2	1000	4	005000090000080324	1
PE10	100001	2	1000	4	005000090000080324	1
PE10	100001	2	1000	4	005000090000080324	1
PE10	100001	2	1000	4	005000090000080324	1
PE10	100001	2	1000	4	005000090000080324	1
PE10	100001	2	1000	4	005000090000080324	1
PE10	100001	2	1000	4	005000090000080324	1
PE10	100001	2	1000	4	005000090000080324	1
PE10	100001	2	1000	4	005000090000080305	1
PE10	100001	2	1000	4	005000090000080305	1
PE10	100001	2	1000	4	005000090000080305	1
PE10	100001	2	1000	4	005000090000080305	1
PE10	100001	2	1000	4	005000090000080305	1
PE10	100001	2	1000	4	005000090000080305	1
PE10	100001	2	1000	4	005000090000080305	1
PE10	100001	2	1000	4	005000090000080305	1
PE10	100001	2	1000	4	005000090000080305	1
PE10	100001	2	1000	4	005000090000080305	1
PE10	100001	2	1000	4	005000090000080305	1
PE10	100001	2	1000	4	005000090000080305	1
PE10	100001	2	1000	4	005000090000080288	1
PE10	100001	2	1000	4	005000090000080288	1
PE10	100001	2	1000	4	005000090000080288	1
PE10	100001	2	1000	4	005000090000080288	1
PE10	100001	2	1000	4	005000090000080288	1
PE10	100001	2	1000	4	005000090000080288	1
PE10	100001	2	1000	4	005000090000080288	1
PE10	100001	2	1000	4	005000090000080288	1
PE10	100001	2	1000	4	005000090000080288	1
PE10	100001	2	1000	4	005000090000080288	1
PE10	100001	2	1000	4	005000090000080288	1
PE10	100001	2	1000	4	005000090000080288	1

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enrique_aeoAsked:
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PortletPaulfreelancerCommented:
Try this:

select
      *
      , dense_rank() over(order by codigoCliente, materialReal) as NEW_COLUMN
from [Copia de Base PG]

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Why are you using 10774 in the question titles?

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for reuse if needed: http://sqlfiddle.com/#!3/16c64/2
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enrique_aeoAuthor Commented:
you can tell the NEW_COLUMN begins with the value of 50

Course 10774A: Querying Microsoft SQL Server 2012
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PortletPaulfreelancerCommented:
I don't understand what this means:

"you can tell the NEW_COLUMN begins with the value of 50"

??? this ???

50 + dense_rank() over(order by codigoCliente, materialReal) as NEW_COLUMN
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Microsoft SQL Server 2008

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