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Passing arguements to call batch file from Vb.Net

Posted on 2014-10-10
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Last Modified: 2014-10-15
I am calling .bat file from Vb.Net by passing Source File and Destination File Folder as Arguements.

If i call .bat file directly from cmd and pass the arguements, .bat file works !! I checked the values passed on the variables and everything looks correct to me. Still i couldn't find why my syntax fails to process the command in the .bat file. I dont get any errors or exceptions.


Dim strSourceFile As String = String.Empty
            strSourceFile = "D:\csv\TestMO.csv"

            Dim strDestPath As String = String.Empty
            strDestPath = "//home/myfolder/myfolder/"

            Dim strUserName As String = String.Empty
            strUserName = "username"

            Dim strPassword As String = String.Empty
            strPassword = "password"

            Dim strHostName As String = String.Empty
            strHostName = "hostname"

            Dim iPort As Integer
            iPort = 22

            Dim sSFTP As String = String.Empty
            sSFTP = "sftp://" & strUserName & ":" & strPassword & "@" & strHostName & ":" & iPort & strDestPath

            Dim strBatchFile As String = String.Empty
            strBatchFile = AppDomain.CurrentDomain.BaseDirectory
            'strBatchFile = strBatchFile.Replace("\bin\Debug", "\ShellScript")
            strBatchFile = strBatchFile & "callsfxcl.bat"

            Dim proc As New System.Diagnostics.Process()
            proc.StartInfo.UseShellExecute = False
            proc.StartInfo.FileName = strBatchFile
            proc.StartInfo.Arguments = String.Format("{0},{1}", strSourceFile, sSFTP)
            proc.StartInfo.CreateNoWindow = True
            proc.StartInfo.WindowStyle = System.Diagnostics.ProcessWindowStyle.Hidden
            proc.Start()

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Question by:chokka
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6 Comments
 
LVL 41

Expert Comment

by:Kyle Abrahams
ID: 40374208
proc.StartInfo.Arguments = String.Format("{0},{1}", strSourceFile, sSFTP)

shouldn't that just be:

 proc.StartInfo.Arguments = String.Format("{0} {1}", strSourceFile, sSFTP)  



eg:

callsfxcl.bat   strSourcefile,sSFTP  
    vs
callsfxcl.bat  strSourcefile sSFTP

what's in the bat file or how do you need the parameters to be called?
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Author Comment

by:chokka
ID: 40375820
Inside the .bat file.



@Echo off


::~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
:: This is the file on the remote site that we will be downloading

Set SRC= %1
Set DST= %2

:: This is the destination folder on the local machine (could be passed in 
:: as a parameter (e.g. %1))

Set SFXCLCMD="C:\Program Files (x86)\V Software\Clients\sfxcl.exe" %SRC% %DST%

:: Now, issue the actual SFXCL command to transfer the file
%SFXCLCMD%

:: Check for Failure
if not %errorlevel%==0 goto TRANSFER_FAILED

:: Success!
Goto Finished

::~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
:TRANSFER_FAILED
FOR /f "tokens=1-3 delims=: " %%a in ('Time /T') do SET CurTime=%%a:%%b%%c
echo.    %CurTime% : Transfer Failure.  
goto End

	
::~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
:Finished
FOR /f "tokens=1-3 delims=: " %%a in ('Time /T') do SET CurTime=%%a:%%b%%c
echo %CurTime% : Transfers Completed successfuly. 

::~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
:End

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Author Comment

by:chokka
ID: 40375825
If i called directly the .bat file from command prompt by providing sourcefile and destinationfile parameters, I am able to see the output. .Bat file is executed correctly.
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LVL 41

Accepted Solution

by:
Kyle Abrahams earned 2000 total points
ID: 40380098
your format is off.

If you're looking for a %1 %2  that's 2 separate parameters.

 proc.StartInfo.Arguments = String.Format("{0},{1}", strSourceFile, sSFTP)  

would read as "mybat.bat SRC,DEST"

you need it to read as "mybat.bat SRC DEST"

which is:
 proc.StartInfo.Arguments = String.Format("{0} {1}", strSourceFile, sSFTP)
0
 

Author Comment

by:chokka
ID: 40380907
@Kyle, Thank you !! I tried both ways. But my hunch is that something went wrong in that specific .exe file. I will try reinstalling the application.
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Author Closing Comment

by:chokka
ID: 40382089
Thanks
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