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validation and formatting using custom directive with angularjs

Posted on 2014-10-15
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Last Modified: 2014-11-08
I am writing custom directive to validate and format the input using angularjs and I stuck in the middle while formatting the input.The valid input must have 3 digits with 2 decimals.Below I have mentioned 3 regex patterns with output format and if user enters any one of the below matching regex pattern and it should format accordingly.
In the directive I am using blur function because I want format/show error message when user leaves the textbox.Please help me to fix this issue.Here is the fiddle.fiddle


            input with reg pattern             output(need to format)

      Ex:      // [/^\d{3}$/] 789  --->               789.00
              // [/^(\d{3})\.(\d{1})$/] 789.4  --->  789.40
                // [/^(\d{3})(\d{2})$/] 78945-->       789.45
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Question by:ksd123
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4 Comments
 
LVL 82

Expert Comment

by:leakim971
ID: 40381874
why a regex?

if(inputvalue) {
   return ((inputvalue.substr(0,3) + "." + inputvalue.substr(3) ) * 1).toFixed(2);
}
return undefined;

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Author Comment

by:ksd123
ID: 40382750
Thank you.I have updated the directive with the above code.It is not working as expected,sometimes I am getting NaN ,if I enter 10 digits it's formatting and giving first 5 digits with 2 decimals which is not valid as it show error message.In  one scenario it is working as expected ie. if user enters 123, it gives 123.00.
Here is the updated fiddle directive.Can you correct me what went wrong?
Below is my requirement
Invalid input
12346789-invalid format
Qswe1234-invalid format

If user enters valid input then it should format
Valid input
123 ---> 123.00
123.4--->123.40
12345--->123.45
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LVL 82

Accepted Solution

by:
leakim971 earned 500 total points
ID: 40383226
test page : http://jsfiddle.net/4HRJu/12/
                   
                     if(inputvalue) {
                         var x = inputvalue;
                         while(x>999) x = x / 10;
                         x = (x+"").split(".");
                         if(x.length<2) x.push("0");
      return ((x[0] + "." + x[1] ) * 1).toFixed(2);

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0
 

Author Comment

by:ksd123
ID: 40383518
Thank you so much,It's working fine in following scenarios
123 ---> 123.00
123.4--->123.40
12345--->123.45

But still it is failing in  following scenarios and want to show expected output (error message) for below scenarios.The valid input must have 3 digits with 2 decimals

i/p                actual o/p     expected o/p
123456-->        123.46             Invalid Format error message
1234567-->      123.46             Invalid Format error message
12            -->      12.00               Invalid Format error message
1              ->         1.00                Invalid Format error message
abcdef    -->     NaN                Invalid Format error message
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