# Average IF

Hi,

Im getting a #DIV/0 on the below formula

=AVERAGEIFS(WinLoss!R:R,WinLoss!BC:BC,"Yes",WinLoss!BA:BA,"Yes",WinLoss!F:F,"<>Renew",WinLoss!W:W,"Lost",WinLoss!W:W,"Cancelled")

Can anyone see why?

Thanks
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Commented:
Hi,

have you tested what the Help says

If average_range is a blank or text value, AVERAGEIFS returns the #DIV0! error value.
If cells in average_range cannot be translated into numbers, AVERAGEIFS returns the #DIV0! error value.
If there are no cells that meet all the criteria, AVERAGEIFS returns the #DIV/0! error value.

Regards
Commented:
WinLoss!W:W,"Lost",WinLoss!W:W,"Cancelled"

Those last two can't both be true at once.
Author Commented:
They can be true, in terms of the data, we can have cancelled and lost, which is what im looking for, must the structure of the IF change?

Thanks
Commented:
I mean one row cannot match both criteria, so you will never get any matches, hence your DIV/0 problem. You would need either SUMIFS / COUNTIFS or use an array version like:
=AVERAGE(IF((WinLoss!BC1:BC1000="Yes")*(WinLoss!BA1:BA1000="Yes")*(WinLoss!F1:F1000<>"Renew")*((WinLoss!W1:W1000="Lost")+(WinLoss!W1:W1000="Cancelled")),WinLoss!R1:R1000))
which is entered with Ctrl+Shift+Enter. Note: do NOT use entire column references with this formula!

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Author Commented:
I get it now!

Out of interest, why cant entire column reference be used?
Commented:
Because it will make the formula calculate really slowly.
Commented:
BTW, you could also use:

=SUM(SUMIFS(WinLoss!R:R,WinLoss!BC:BC,"Yes",WinLoss!BA:BA,"Yes",WinLoss!F:F,"<>Renew",WinLoss!W:W,{"Lost","Cancelled"}))/SUM(COUNTIFS(WinLoss!BC:BC,"Yes",WinLoss!BA:BA,"Yes",WinLoss!F:F,"<>Renew",WinLoss!W:W,{"Lost","Cancelled"}))
Author Commented:
That all makes sense, thanks Rory!
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