Solved

# SQL with Subqueries

Posted on 2014-10-17
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Hi!

I try to run this SQL:

1. SELECT EBELN, EBELP, BWART, CHARG, MATNR, MJAHR, MENGE, MEINS, WERKS
2. FROM [ENLIST_WH_SQL].[dbo].[MSEG] WHERE EBELN + EBELP IN
3. (SELECT COUNT(MANDT) AS NumberOut, EBELN + EBELP
4. FROM [ENLIST_WH_SQL].[dbo].[MSEG]
5. WHERE (BWART = '643' OR BWART = '641' OR BWART = '161') AND MATNR > '000000003500000000' AND MATNR
6. < '000000006900000000' GROUP BY EBELN + EBELP) x INNER JOIN
7. (SELECT COUNT(MANDT), EBELN + EBELP
8. FROM [ENLIST_WH_SQL].[dbo].[MSEG]
9. WHERE BWART = '101' OR BWART = '644' OR BWART = '102' GROUP BY EBELN + EBELP) y ON x.EBELN + x.EBELP =
10. y.EBELN + y.EBELP
11. WHERE y.COUNT(MANDT) < x.COUNT(MANDT)

but get the error:

Msg 170, Level 15, State 1, Line 5
Line 5: Incorrect syntax near 'x'.
Msg 170, Level 15, State 1, Line 8
Line 8: Incorrect syntax near 'y'.

This is what I try to obtain in human text:
Select all interrelated EBELN + EBELP (3.) and count how many occurences with COUNT(MANDT). This seach is related to x.
Select all interrelated EBELN + EBELP (7.) with other filter criterias in the same table and count how many occurences with COUNT(MANDT). This seach is related to y.
The x and y are joined and the counts is used to filter (11.)
Finally this combined search result is used to get BWART, CHARG, MATNR, MJAHR, MENGE, MEINS, WERKS from the same table MSEG (1.).

Perhaps it is too ambitious to retrieve all this information in one SQL but in order to be usable in our situation, it must be in one retrieval.

Any ideas to solve this?
0
Question by:Kim Neesgaard
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LVL 15

Expert Comment

ID: 40386352
Try using temp tables since like this is bit complicated and complex to maintain...

Is this what you are after:

``````SELECT COUNT(MANDT) AS NumberOut, EBELN + EBELP as value
into #X
FROM [ENLIST_WH_SQL].[dbo].[MSEG]
WHERE (BWART = '643' OR BWART = '641' OR BWART = '161') AND MATNR > '000000003500000000' AND MATNR < '000000006900000000'
GROUP BY EBELN + EBELP

SELECT COUNT(MANDT) AS NumberOut, EBELN + EBELP as value
into #Y
FROM [ENLIST_WH_SQL].[dbo].[MSEG]
WHERE BWART = '101' OR BWART = '644' OR BWART = '102'
GROUP BY EBELN + EBELP

SELECT EBELN, EBELP, BWART, CHARG, MATNR, MJAHR, MENGE, MEINS, WERKS
FROM [ENLIST_WH_SQL].[dbo].[MSEG]
WHERE EBELN + EBELP IN
(select X.VALUE
FROM #X INNER JOIN #y ON x.VALUE =  y.VALUE
WHERE y.NumberOut < x.NumberOut )
``````
0

Author Comment

ID: 40386370
Hi samo4fun!

I have tried to run your suggestion and get this message:

(158122 row(s) affected)

(1886804 row(s) affected)
Msg 107, Level 16, State 2, Line 14
The column prefix 'X' does not match with a table name or alias name used in the query.
Msg 107, Level 16, State 2, Line 14
The column prefix 'y' does not match with a table name or alias name used in the query.
Msg 107, Level 16, State 2, Line 14
The column prefix 'x' does not match with a table name or alias name used in the query.
Msg 107, Level 16, State 2, Line 14
The column prefix 'x' does not match with a table name or alias name used in the query.
Msg 107, Level 16, State 2, Line 14
The column prefix 'y' does not match with a table name or alias name used in the query.

Do you have suggestions to this?
0

LVL 51

Expert Comment

ID: 40386375
You can't do it as you did. Here's a single statement solution using common table expression:
``````WITH x (EBELN_EBELP, NumberOut)
AS
(SELECT (EBELN + EBELP), COUNT(MANDT) AS
FROM [ENLIST_WH_SQL].[dbo].[MSEG]
WHERE (BWART = '643' OR BWART = '641' OR BWART = '161')
AND MATNR > '000000003500000000' AND MATNR < '000000006900000000'
GROUP BY (EBELN + EBELP)),
y (EBELN_EBELP, NumberOut) AS
(SELECT (EBELN + EBELP), COUNT(MANDT) AS NumberOut
FROM [ENLIST_WH_SQL].[dbo].[MSEG]
WHERE (BWART = '101' OR BWART = '644' OR BWART = '102' )
GROUP BY (EBELN + EBELP))

SELECT m.EBELN, m.EBELP, m.BWART, m.CHARG, m.MATNR, m.MJAHR, m.MENGE, m.MEINS, m.WERKS, x.EBELN_EBELP, x.NumberOut, y.EBELN_EBELP, y.NumberOut
FROM [ENLIST_WH_SQL].[dbo].[MSEG] m
LEFT OUTER JOIN x ON x.EBELN_EBELP = m.EBELN + m.EBELP
LEFT OUTER JOIN y ON y.EBELN_EBELP = m.EBELN + m.EBELP
``````
0

Author Comment

ID: 40386379
Hi!

I tried to run the 3 parts in a SQL Server 2008 window and I have tried the same with your new suggestion - it gives me this:

Msg 156, Level 15, State 1, Line 1
Incorrect syntax near the keyword 'WITH'.
Msg 156, Level 15, State 1, Line 4
Incorrect syntax near the keyword 'FROM'.

Line 15: FROM [ENLIST_WH_SQL].[dbo].[MSEG] m
0

LVL 49

Expert Comment

ID: 40386381
try this. Without any data to test against I can't guarantee it's correct, but I think it's true to your intent.

``````SELECT
m.EBELN
, m.EBELP
, m.BWART
, m.CHARG
, m.MATNR
, m.MJAHR
, m.MENGE
, m.MEINS
, m.WERKS
FROM [ENLIST_WH_SQL].[dbo].[MSEG] m
INNER JOIN (
SELECT
COUNT(CASE WHEN BWART IN ('161', '641', '643') THEN MANDT END) AS x
, COUNT(CASE WHEN BWART IN ('101', '102', '644') THEN MANDT END) AS y
, EBELN
, EBELP
FROM [ENLIST_WH_SQL].[dbo].[MSEG]
WHERE MATNR > '000000003500000000'
AND MATNR < '000000006900000000'
GROUP BY
EBELN
, EBELP
) derived
ON m.EBELN = derived.EBELN
AND m.EBELP = derived.EBELP
AND derived.y < derived.x
;
``````
0

LVL 51

Expert Comment

ID: 40386382
Try to put a ';' before the WITH keyword:
``````;WITH x (EBELN_EBELP, NumberOut)
AS
(SELECT (EBELN + EBELP), COUNT(MANDT) AS
FROM [ENLIST_WH_SQL].[dbo].[MSEG]
WHERE (BWART = '643' OR BWART = '641' OR BWART = '161')
AND MATNR > '000000003500000000' AND MATNR < '000000006900000000'
GROUP BY (EBELN + EBELP)),
y (EBELN_EBELP, NumberOut) AS
(SELECT (EBELN + EBELP), COUNT(MANDT) AS NumberOut
FROM [ENLIST_WH_SQL].[dbo].[MSEG]
WHERE (BWART = '101' OR BWART = '644' OR BWART = '102' )
GROUP BY (EBELN + EBELP))

SELECT m.EBELN, m.EBELP, m.BWART, m.CHARG, m.MATNR, m.MJAHR, m.MENGE, m.MEINS, m.WERKS, x.EBELN_EBELP, x.NumberOut, y.EBELN_EBELP, y.NumberOut
FROM [ENLIST_WH_SQL].[dbo].[MSEG] m
LEFT OUTER JOIN x ON x.EBELN_EBELP = m.EBELN + m.EBELP
LEFT OUTER JOIN y ON y.EBELN_EBELP = m.EBELN + m.EBELP
``````
0

Author Comment

ID: 40386402
The 12:02 still gives an error but 12:03 runs without errors. Thank you so far - I will check the result of the query and come back!
0

Author Comment

ID: 40386403
Sorry - the oppersite: 12:02 runs without error.
0

LVL 51

Expert Comment

ID: 40386404
What's the error?
0

LVL 49

Accepted Solution

PortletPaul earned 500 total points
ID: 40386405
I think mine may need an additon to a where clause

``````SELECT
m.EBELN
, m.EBELP
, m.BWART
, m.CHARG
, m.MATNR
, m.MJAHR
, m.MENGE
, m.MEINS
, m.WERKS
FROM [ENLIST_WH_SQL].[dbo].[MSEG] m
INNER JOIN (
SELECT
COUNT(CASE WHEN BWART IN ('161', '641', '643') THEN MANDT END) AS x
, COUNT(CASE WHEN BWART IN ('101', '102', '644') THEN MANDT END) AS y
, EBELN
, EBELP
FROM [ENLIST_WH_SQL].[dbo].[MSEG]
WHERE MATNR > '000000003500000000'
AND MATNR < '000000006900000000'
AND BWART IN ('101', '102', '644', '161', '641', '643')  --<< added
GROUP BY
EBELN
, EBELP
) derived
ON m.EBELN = derived.EBELN
AND m.EBELP = derived.EBELP
AND derived.y < derived.x
;
``````
0

Author Comment

ID: 40391768
->  PortletPaul
I have now investigated the search result and it looks REALLY good. I will do   some further investigations and come back.

Thanks for the help!
0

Author Comment

ID: 40419327

SELECT EBELN, EBELP, BWART, CHARG, MATNR, MJAHR, MENGE, MEINS, WERKS
FROM [ENLIST_WH_SQL].[dbo].[MSEG] WHERE EBELN + EBELP IN
(SELECT COUNT(MANDT) AS NumberOut, EBELN + EBELP
FROM [ENLIST_WH_SQL].[dbo].[MSEG]
WHERE (BWART = '643' OR BWART = '641' OR BWART = '161') AND MATNR > '000000003500000000' AND MATNR < '000000006900000000') x INNER JOIN
(SELECT COUNT(MANDT), EBELN + EBELP
FROM [ENLIST_WH_SQL].[dbo].[MSEG]
WHERE BWART = '101' OR BWART = '644' OR BWART = '102') y ON x.EBELN + x.EBELP = y.EBELN + y.EBELP
WHERE y.COUNT(MANDT) < x.COUNT(MANDT) GROUP BY EBELN + EBELP

but when I run it today, I get the error:

Msg 170, Level 15, State 1, Line 5
Line 5: Incorrect syntax near 'x'.
Msg 170, Level 15, State 1, Line 8
Line 8: Incorrect syntax near 'y'.

0

LVL 51

Expert Comment

ID: 40419339
Check if you aren't running an old version of the script.
0

LVL 49

Expert Comment

ID: 40419341
Nope. Sorry.
That query is badly formed and I have no idea what you are trying to achieve with it.
0

Author Comment

ID: 40419475
I am very sorry - I had selected a wrong SQL (I had tried to make myself) by mistake and therefore it was badly formed. Once again: my apologies!

I found the SQL based on your very well formed SQL and it works perfectly!
0

LVL 49

Expert Comment

ID: 40515493
Kim,

Thank you for selecting my solution as the answer - but can you tell me why you believe it is a B Grade?
0

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