Solved

Trying to set a variable in a SQL Statement from with the SELECT?

Posted on 2014-10-21
5
81 Views
Last Modified: 2014-10-21
What I need to do is assign the value from "createdBy_ID" to a variable @user_ID but not sure how to do it. Where can I find some good tutorials on PL-SQL? Also, I'm using SQL Server 2012 instead of 2008.

Thanks!

        DECLARE @user_ID               INT=NULL

	IF EXISTS(SELECT userAccount_ID, createdBy_ID FROM USER_Permissions WHERE userAccount_ID = @userAccount_ID AND menuItem_ID = @menuItem_ID)
		BEGIN
			UPDATE	USER_Permissions
			   SET	allowUpdate = @iUpdate
					,allowView = @iView
                                        ,createdBy_ID = @user_ID
					,updatedBy_ID = @updatedBy_ID
					,dateUpdated = GETDATE()
			 WHERE	userAccount_ID = @userAccount_ID AND menuItem_ID = @menuItem_ID
		END
	ELSE

Open in new window

0
Comment
Question by:BlakeMcKenna
5 Comments
 
LVL 15

Accepted Solution

by:
Haris Djulic earned 500 total points
ID: 40395435
here is the requested code

        DECLARE @user_ID               INT=NULL

	IF EXISTS(SELECT userAccount_ID, createdBy_ID FROM USER_Permissions WHERE userAccount_ID = @userAccount_ID AND menuItem_ID = @menuItem_ID)
		BEGIN
		
		set @user_ID =(SELECT  createdBy_ID FROM USER_Permissions WHERE userAccount_ID = @userAccount_ID AND menuItem_ID = @menuItem_ID)
			UPDATE	USER_Permissions
			   SET	allowUpdate = @iUpdate
					,allowView = @iView
                    ,createdBy_ID = @user_ID
					,updatedBy_ID = @updatedBy_ID
					,dateUpdated = GETDATE()
			 WHERE	userAccount_ID = @userAccount_ID AND menuItem_ID = @menuItem_ID
		END
	ELSE

Open in new window

0
 
LVL 7

Expert Comment

by:slubek
ID: 40395447
I'm not sure what are you trying to achieve, but what about

...
,createdBy_id = SYSTEM_USER
...

Open in new window

?
0
 
LVL 26

Expert Comment

by:Shaun Kline
ID: 40395548
If all you are doing is setting the CreatedBy field to the existing value, you can just exclude that field from your update statement.
0
 
LVL 69

Expert Comment

by:Scott Pletcher
ID: 40395569
>> Where can I find some good tutorials on PL-SQL? <<

Hmm, since PL/SQL is Oracle's language, presumably an Oracle site?

SQL's code, as you've written, is T-SQL (Transact SQL).


@user_ID, and the other variables, needs a value assigned or you will just INSERT NULL values.  You need to either pass those variables as parameters to the proc or assign them values in the proc.

Then, you can just issue the UPDATE without checking first: if there's no matching row, none will be UPDATEd.


UPDATE      USER_Permissions
   SET      allowUpdate = @iUpdate
            ,allowView = @iView
            ,createdBy_ID = @user_ID
            ,updatedBy_ID = @updatedBy_ID
            ,dateUpdated = GETDATE()
  WHERE      userAccount_ID = @userAccount_ID AND menuItem_ID = @menuItem_ID
0
 

Author Closing Comment

by:BlakeMcKenna
ID: 40395908
This is what I was looking for. The other answers made sense but the logic of the program is such that I need to handle it in the SP.

Thanks samo!
0

Featured Post

Free Tool: Site Down Detector

Helpful to verify reports of your own downtime, or to double check a downed website you are trying to access.

One of a set of tools we are providing to everyone as a way of saying thank you for being a part of the community.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Long way back, we had to take help from third party tools in order to encrypt and decrypt data.  Gradually Microsoft understood the need for this feature and started to implement it by building functionality into SQL Server. Finally, with SQL 2008, …
Naughty Me. While I was changing the database name from DB1 to DB_PROD1 (yep it's not real database name ^v^), I changed the database name and notified my application fellows that I did it. They turn on the application, and everything is working. A …
Although Jacob Bernoulli (1654-1705) has been credited as the creator of "Binomial Distribution Table", Gottfried Leibniz (1646-1716) did his dissertation on the subject in 1666; Leibniz you may recall is the co-inventor of "Calculus" and beat Isaac…

789 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question