sql - return date

I want below to return the date of a month ago or whatever the @numofmonth is.

declare @Date as datetime
DECLARE @NumOfMonth AS int
set @NumOfMonth = 1
set @Date = (dateadd(dd,-datepart(dd,getdate())+ 1,dateadd(mm,-@NumOfMonth,getdate())))
print @date

This returns Sep  1 2014 11:39AM
VBdotnet2005Asked:
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Jim HornMicrosoft SQL Server Developer, Architect, and AuthorCommented:
So how does there year come into play?   Assuming the YEAR(GETDATE()),
DECLARE @NumOfMonth AS int = 1

Declare @dt date = CAST(GETDATE() as date) 

declare @dt_passed_month as date 

SET @dt_passed_month = CAST(CAST(YEAR(@dt) as char(4)) + '-' + RIGHT('0' + CAST(@NumOfMonth as varchar(2)),2) + '-01' as date) 

PRINT DATEADD(m, -1, @dt_passed_month)

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Scott PletcherSenior DBACommented:
Don't mess with strings, they will slow you down and depend on regional settings.  Instead, use straight "date math" ... which is simpler and more consistent anyway once you get used to it :-).


DECLARE @Date as datetime
DECLARE @NumOfMonth AS int

SET @NumOfMonth = 1
SET @Date = DATEADD(MONTH, @NumOfMonth - 1, DATEADD(YEAR, YEAR(GETDATE()) - 1900, 0))

PRINT @date
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Microsoft SQL Server 2008

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