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Ajax.BeginForm ActionResult Task Delay Goto?

Posted on 2014-10-23
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Last Modified: 2014-10-27
I need to delay the ActionResult return Content until all the Tasks are completed. I like the way the Ajax.BeginForm uses the LoadingElementId to start the spinner.gif. The problem is the ActionResult returns before the Tasks are complete, so the spinner is useless.

[View]
   @using (Ajax.BeginForm("Import", "Books", new AjaxOptions { HttpMethod = "Post", UpdateTargetId = "result", LoadingElementId = "loading"}))
{
   ...
}

<div id="loading">
       <img src="~/Content/Images/spinner.gif" height="30" />
</div>

[Action]
    public async Task<ActionResult> Import(ImportViewModel model)
    {
           bool books = false; 

           foreach(....)
           {
                  books = await ImportBooks();
            }

           wait:

                Task.Delay(5000).Wait();

                if (books == false)
                {
                    goto wait;
                }
                else                    
                    return Content("Books import completed!");            
     }

     public async Task<bool> ImportBooks()
     {
          ....
          await context.SaveChangesAsync();

         return true;
     }

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Question by:WorknHardr
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5 Comments
 
LVL 58

Expert Comment

by:Julian Hansen
ID: 40403066
You probably want to be looking at the AjaxOptions onComplete

http://msdn.microsoft.com/en-us/library/system.web.mvc.ajax.ajaxoptions.oncomplete%28v=vs.118%29.aspx

You create a handler for the onComplete event and disable your spinner there.
0
 

Author Comment

by:WorknHardr
ID: 40403159
I have a problem with the Action completing before I want it to.
I've been looking into await Task.WhenAll(????) , unsure how to implement it so far..
0
 
LVL 58

Accepted Solution

by:
Julian Hansen earned 2000 total points
ID: 40406058
That is why I suggested the onComplete - this is called when the AJAX call is completed - have you tried implementing an onComplete handler?
Alternatively look at onSuccess

@using (Ajax.BeginForm("Import", "Books", new AjaxOptions { HttpMethod = "Post", UpdateTargetId = "result", LoadingElementId = "loading", OnSuccess="ProcessHere"}))
{

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Inside the ProcessHere method - implement the code you want to run after call completed.
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Author Closing Comment

by:WorknHardr
ID: 40406223
Thx, I'll give that a go...
0
 
LVL 58

Expert Comment

by:Julian Hansen
ID: 40406286
You are welcome - good luck with it.
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