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HashMap - Converting long string values to smaller codes

Posted on 2014-10-24
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Last Modified: 2014-10-25
hi experts

I have a Map<String,String>
Key  value
1      Prl-transaction Inc. Adjust,Prl-transaction  Inc,Prl-transaction POPO Inc.,eer yy uuu,iii  - TESTCLUSTER
2      Prl-transaction Inc. Adjust,Prl-transaction  Inc,Prl-transaction POPO Inc.,eer yy uuu,iii  - TESTCLUSTER_GMC,RRRRR
3      Prl-transaction Inc. Adjust,Prl-transaction  Inc,Prl-transaction POPO Inc.,eer yy uuu,iii  - TESTCLUSTER
4      Prl-transaction Inc. Adjust,Prl-OGRMAA  Inc,Prl-transaction POPO Inc.,eer yy uuu,iii  - TESTCLUSTER


As you can see  The 'value' in the Map can be very long.

What i want to do is create a new Map with short codes for values something like

Key     value
1       Prl-transaction1
2       Prl-transaction2
3       Prl-transaction1
4       Prl-transaction3

where
Prl-transaction1 = Prl-transaction Inc. Adjust,Prl-transaction  Inc,Prl-transaction POPO Inc.,eer yy uuu,iii  - TESTCLUSTER
Prl-transaction2 = Prl-transaction Inc. Adjust,Prl-transaction  Inc,Prl-transaction POPO Inc.,eer yy uuu,iii  - TESTCLUSTER_GMC,RRRRR
Prl-transaction3 = Prl-transaction Inc. Adjust,Prl-OGRMAA  Inc,Prl-transaction POPO Inc.,eer yy uuu,iii  - TESTCLUSTER

* The value for key 1 and 3 are same since they are the same string.

Any idea how i can do that?

Any help will be greatly appreciated
thanks.
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Question by:royjayd
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7 Comments
 
LVL 32

Expert Comment

by:awking00
ID: 40402493
Are the keys in the map unique? Your example shows different keys mapping to the same value, but can you have the same key mapping to different values?
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Author Comment

by:royjayd
ID: 40402622
>>Are the keys in the map unique?
Key in Map is always unique, isint it ?
In my code above Key is 1,2,3,4

Each key can only be mapped to one value.
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LVL 32

Expert Comment

by:awking00
ID: 40402647
Also, are your keys actually Strings or are they ints?
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LVL 32

Accepted Solution

by:
awking00 earned 2000 total points
ID: 40402758
>>Each key can only be mapped to one value.<<
DOH!  Of course they must. Guess I was having a little brain cramp. How was your map constructed (e.g. as HashMap or TreeMap, or whatever)?
0
 

Author Comment

by:royjayd
ID: 40403411
no worries , i got it working.
I will give you the points for your time.
Thank you.
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LVL 32

Expert Comment

by:awking00
ID: 40404001
Thanks for the points. Could I see what you ended up with as I have been working on the solution but it's not been completed yet?
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LVL 32

Expert Comment

by:awking00
ID: 40404056
Not very elegant, but I got this to work using a temporary map -
import java.util.Collection;
import java.util.Map;
import java.util.Set;
import java.util.TreeMap;

@SuppressWarnings("unused")
public class TestMap {

	public static Map<String, String> map = new TreeMap<String, String>();
	public static Map<String, String> tempMap = new TreeMap<String, String>();
	public static Map<String, String> newMap = new TreeMap<String, String>();
	public static Collection values;

	public static void main(String[] args) {
		map.put("1","Prl-transaction Inc. Adjust,Prl-transaction  Inc,Prl-transaction POPO Inc.,eer yy uuu,iii  - TESTCLUSTER");
		map.put("2","Prl-transaction Inc. Adjust,Prl-transaction  Inc,Prl-transaction POPO Inc.,eer yy uuu,iii  - TESTCLUSTER_GMC,RRRRR");
		map.put("3","Prl-transaction Inc. Adjust,Prl-transaction  Inc,Prl-transaction POPO Inc.,eer yy uuu,iii  - TESTCLUSTER");
		map.put("4","Prl-transaction Inc. Adjust,Prl-OGRMAA  Inc,Prl-transaction POPO Inc.,eer yy uuu,iii  - TESTCLUSTER");

		values = map.values();
		String[] vals = (String[]) values.toArray(new String[0]);
		for (String key : map.keySet()) {
			for (String val : vals) {
				if (map.get(key).toString().equals(val) && !tempMap.containsValue(val))
				{
					tempMap.put(key, val);
					newMap.put(key, val.substring(0, val.indexOf(" ")) + key);
				} else if  (map.get(key).toString().equals(val) && tempMap.containsValue(val))
				{
					String oldKey = getOldKey(val);
					newMap.put(key, val.substring(0, val.indexOf(" ")) + oldKey);
				}
			}
		}
		System.out.println(newMap.toString());
	}
	
	public static String getOldKey(String val) {
		String replaceKey = null;
		for (String oldKey : tempMap.keySet()) {
			if (tempMap.get(oldKey).toString().equals(val)) {
				replaceKey = oldKey;
			}
		}
		return replaceKey;
	}
}

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