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SSRS Stacked Column Chart is too High

Posted on 2014-10-28
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Last Modified: 2014-10-28
Hello Experts Exchange
I have a chart that is a Stacked Column Chart.  The problem I have is the red column is going higher than it should.

Take a look at my image I have attached.

You will see the green column that is correct for all categories, but the red is wrong for every one.

The red column should match the table on the right of the column chart.

So for example UKL should be 2196 but on the column chart it is over 2500.

How do I get it to show the correct value?

Regards

SQLSearcher
Stacked-Column-Chart.jpg
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Question by:SQLSearcher
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Expert Comment

by:Phillip Burton
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The problem is that it is a stacked chart. This means that the red bar starts where the green one ends. Because the green bar is about 400, the means that the red bar goes from 400-2600.
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Expert Comment

by:Phillip Burton
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You therefore need to change it to a column or a 3D column chart if you don't want it stacked.
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Author Comment

by:SQLSearcher
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Hello Phillip
Is there a chart type that will do what I want to do?

Regards

SQLSearcher
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Expert Comment

by:Phillip Burton
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Depends on what you want to do. I've given you two alternatives, but if they aren't useful, then you need to say what's wrong with them.
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Author Comment

by:SQLSearcher
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Hi Phillip
Can I use a Column chart and instead of having the columns siting side by side can I have the green column in front of the red column?  If so how do I achieve that?

Regards

SQLSearcher
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Accepted Solution

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Phillip Burton earned 500 total points
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First of all, Change Chart Type to the standard Column (which looks like it is side-by-side).

Make sure you can see the Properties window (press F4 if you can't see it).

Then click on the second data series (the one which is to the right of the other one).

In the Properties window, expand General - CustomAttributes, and change DrawSideBySide to False.

Then preview the report. If you can't see the green bars, then back in Design, in the Chart Data window, drag your first set of values down below the second set.
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Author Closing Comment

by:SQLSearcher
Comment Utility
Thank you Phillip, for your help.
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