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In Vector CANoe trace, which is Bit 0,  Bit 63 ?

Posted on 2014-10-30
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Last Modified: 2014-10-30
Here is the Vector CANoe trace:

Tx      03  22  F1  00   00  00  00  00
Rx      07  42  E1  00  00  22   44  01

In any of the above 8 bytes messages, which is bit 0 and which is bit 63 ?
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Question by:naseeam
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jkr earned 500 total points
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Assuming that the above is something that you get displayed (and not a 'raw' memory dump), bit 0 is always the lowest value bit, i.e. in Rx as  '07  42  E1  00  00  22   44  01' it is the rightmost '1' and in Tx as '03  22  F1  00   00  00  00  00' it is the leftmost zero. In both cases, bit 64 - the leftmost value - is not set.
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by:naseeam
ID: 40414302
>>   and in Tx as '03  22  F1  00   00  00  00  00' it is the leftmost zero.

Do you mean rightmost zero ?
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by:jkr
ID: 40414318
Yes, sorry, that should have been the 'rightmost' as well.

BTW, you can programatically obtain these values via bitwise AND operations, e.g.

#define MSB_64(x) (x & 0x8000000000000000) // bit 63, the Most Significant Bit
#define LSB_64(x) (x & 0x0000000000000001) // bit 0, the Least Significant Bit

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