partition table when: delete and re-create the cluster index???

i have this database

CREATE DATABASE dbPart ON  PRIMARY
( NAME = 'dbPart', FILENAME = N'c:\SQLDATA\dbPart.mdf' , SIZE = 3072KB , FILEGROWTH = 1024KB )
 LOG ON
( NAME = 'dbPart_log', FILENAME = N'c:\SQLLOG\dbPart_log.ldf' , SIZE = 1024KB , FILEGROWTH = 10%)

--Creación de los FileGroup
USE master
GO
ALTER DATABASE dbPart ADD FILEGROUP PFG01
GO
ALTER DATABASE dbPart ADD FILEGROUP PFG02
GO
ALTER DATABASE dbPart ADD FILEGROUP PFG03
GO
ALTER DATABASE dbPart ADD FILEGROUP PFG04
GO
ALTER DATABASE dbPart ADD FILEGROUP PFG05
GO

--Creación de los DataFile
ALTER DATABASE dbPart ADD FILE
( NAME = N'PDF01', FILENAME = N'C:\SQLDATA\PDF01.ndf' , SIZE = 3072KB , FILEGROWTH = 1024KB ) TO FILEGROUP PFG01
GO
ALTER DATABASE dbPart ADD FILE
( NAME = N'PDF02', FILENAME = N'C:\SQLDATA\PDF02.ndf' , SIZE = 3072KB , FILEGROWTH = 1024KB ) TO FILEGROUP PFG02
GO
ALTER DATABASE dbPart ADD FILE
( NAME = N'PDF03', FILENAME = N'C:\SQLDATA\PDF03.ndf' , SIZE = 3072KB , FILEGROWTH = 1024KB ) TO FILEGROUP PFG03
GO
ALTER DATABASE dbPart ADD FILE
( NAME = N'PDF04', FILENAME = N'C:\SQLDATA\PDF04.ndf' , SIZE = 3072KB , FILEGROWTH = 1024KB ) TO FILEGROUP PFG04
GO
ALTER DATABASE dbPart ADD FILE
( NAME = N'PDF05', FILENAME = N'C:\SQLDATA\PDF05.ndf' , SIZE = 3072KB , FILEGROWTH = 1024KB ) TO FILEGROUP PFG05
GO

--**********************
I think a table with data, I believe the partition function, I create the partition scheme and the table is partitioned automatically, why?
I expected the partition table when: delete and re-create the cluster index

use dbPart
go

CREATE TABLE [dbo].tabla_demo
(  
id int identity primary key,    
c varchar(200) NULL
)

--2
declare @i int
set @i = 1
while @i<=2 -- Luego 1.000.000 filas
begin        
      INSERT INTO dbo.tabla_demo
      SELECT top (50000)      
               replace(cast(NEWID() as varchar(100)), '-','') + REPLICATE('a', 200-32)    
      FROM AdventureWorks.Sales.SalesOrderHeader   CROSS JOIN AdventureWorks.Sales.SalesOrderDetail
      print cast (@i as varchar(100))  
      set @i=@i+1
end

select * from dbo.tabla_demo

--3
CREATE PARTITION FUNCTION pfPartEE (int)
AS RANGE LEFT FOR VALUES (10000, 20000, 30000, 40000)

--4
CREATE PARTITION SCHEME psPartEE
AS PARTITION pfPartEE
TO (pfg01, pfg02, pfg03, pfg04, pfg05)

      SELECT $PARTITION.pfPartEE(id) AS Particion,
      COUNT(*) AS NumeroRegistros FROM tabla_demo
      GROUP BY $PARTITION.pfPartEE(id)
      ORDER BY Particion
enrique_aeoAsked:
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Barry CunneyCommented:
Hi Enrique,
Typically when creating a new table one would specify the partition scheme as part of the 'CREATE TABLE....' statement.
So in your context, something like the following:
CREATE TABLE [dbo].tabla_demo
(  
id int identity primary key,    
c varchar(200) NULL
) ON psPartEE  (id)

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Please confirm that your point is that your table was automatically partitioned, even though you did not explicitly specify any partitioning details for the table.
0
enrique_aeoAuthor Commented:
Many thanks for responding:

The scenario is as follows:
1. The table has data from 2005 year
2. You want to partition the table

to do this I believed it eliminated the index cluster and re create the index, then data were to go to their respective partition.
0
enrique_aeoAuthor Commented:
hi Barry

as I can partition a table that already contains data?
0
Barry CunneyCommented:
Hi Enrique,
Yes you can partition an existing table by creating an index on the partition scheme.
The following is an example:
CREATE CLUSTERED INDEX IX_table_demo_partitioncol ON dbo.table_demo (partitioncol)
  WITH (STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, 
        ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) 
  ON psPartEE(partitioncol)

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0

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