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C# DateDiff in Months

Posted on 2014-11-06
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Last Modified: 2014-11-12
I need to get the difference in months between two dates.

In SQL, this is what I need:
select DATEDIFF(MONTH, '11/1/2014', DATEADD(mm, DATEDIFF(mm, 0, '12/31/2014') + 1, 0)) 

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The above date difference should be 2 months.
Difference between 12/10/2014 and 12/20/2014 = 1 month.
Difference between 11/1/2012 and 12/31/2014 = 26 months.

How do I do the same in C#?
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Question by:pzozulka
2 Comments
 
LVL 14

Accepted Solution

by:
Vel Eous earned 250 total points
ID: 40427398
The following should give what you are looking for:

namespace EE.Q_28552505.ConsoleApp
{
    using System;

    internal class Program
    {
        private static void Main(string[] args)
        {
            var dateTimeA = new DateTime(2013, 11, 1);
            var dateTimeB = DateTime.UtcNow;

            var difference = ((dateTimeB.Year - dateTimeA.Year) * 12) + dateTimeB.Month - dateTimeA.Month;

            Console.WriteLine(difference); // output is 12

            Console.ReadKey();
        }
    }
}

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0
 
LVL 49

Assisted Solution

by:Gustav Brock
Gustav Brock earned 250 total points
ID: 40434947
Assuming there is some specifics behind the "custom" calculation, it is probably much more straight-forward to mimic it in VB.NET:
using System;
using Microsoft.VisualBasic;

namespace DateDiff
{
    class Program
    {
        static void Main(string[] args)
        {
            DateTest test = new DateTest ();

            //DateTime date1 = new DateTime(2014,11,1);
            //DateTime date2 = new DateTime(2014,12,21);
            //DateTime date1 = new DateTime(2014, 12, 10);
            //DateTime date2 = new DateTime(2014, 12, 20);
            DateTime date1 = new DateTime(2012, 11, 1);
            DateTime date2 = new DateTime(2014, 12, 21);

            long diff = test.DDiff(date1, date2);
            Console.WriteLine(diff.ToString());
            Console.Read();
        }
    }

    public class DateTest
    {
      
        public long DDiff(DateTime Date1,DateTime Date2) 
        {
            DateTime dat0 = new DateTime(1899, 12, 30);
            return DateAndTime.DateDiff("M", Date1, DateAndTime.DateAdd("M", DateAndTime.DateDiff("M", dat0, Date2) + 1, dat0));
        }

    }

}

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This returns the expected results.

/gustav
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