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PHP Echo array question

Posted on 2014-11-07
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Last Modified: 2014-11-16
Having a hard time to echo $agentsStuff within this line of code:

schema (echo $agentsStuff[bizID]1,10);

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Question by:seopti
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5 Comments
 
LVL 111

Expert Comment

by:Ray Paseur
ID: 40429212
Please run this PHP instruction and post the output here, thanks.

<?php var_dump($agentsStuff);

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Author Comment

by:seopti
ID: 40429264
I have a bizID for each business in the database which I can echo with:

<?php echo $agentsStuff['bizID'];?>

Now I've installed an addon which adds schema org. It is printed this way:

<?php schema('someItemID');      //print schema.org rich snippets  ?>

What I would like to do is to echo the bizID as someItemID. I tried this for a few hours without success.
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LVL 111

Expert Comment

by:Ray Paseur
ID: 40429527
I tried this for a few hours without success.
Don't waste your time like that.  Just work with me.

Please run this PHP instruction and post the output here, thanks.

<?php var_dump($agentsStuff);

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Author Comment

by:seopti
ID: 40430390
When I do var_dump  on $agentsStuff I get:

array(30) { [0]=> string(6) "624082" ["bizID"]=> string(6) "624082" [1]=> string(9) "Attorneys" ["bizCatSub"]=> string(9) "Attorneys" [2]=>  .....

And there is the bizID which I need echoed as someItemID.
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LVL 111

Accepted Solution

by:
Ray Paseur earned 2000 total points
ID: 40430449
It looks like you've got a results set from a query, and you've used MySQL_Fetch_Array() to retrieve the data.  That's an AntiPractice (see number 27 for an explanation of why you want to change that).

To get a different column name in the results set, and therefore a different key in the array, you can change your query to use the AS clause in the SELECT query.  Example:

SELECT bizID AS someItemID FROM myTable...

I don't understand part of this question about this line of code:
schema (echo $agentsStuff[bizID]1,10);

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What is schema()?  Is it some kind of locally defined function?  What does "1,10" mean in this context?
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