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Pivot Data Of Table By Month/Or Week

Posted on 2014-11-08
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Last Modified: 2014-11-15
hi
i simply have table My_Trans
Trans_ID number
Branch_No Number
Trans_Amount Number
Trans_Date Date

how i can generate pivot query from the above table like this :
Branch        Jan       Feb     Mar   Apr
01                1500   1300   2000 3000
02                2000   1000   2000 4000
03                3000    1500  3000  4500 

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same requirement for week number of the year
note : database i'm connection to is 9i
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Question by:NiceMan331
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9 Comments
 
LVL 31

Expert Comment

by:awking00
ID: 40430330
select * from (
 select branch_no, trans_amount, to_char(trans_date,'MON') month
 from my_trans)
pivot
(
 sum(trans_amount)
 for month in ('JAN','FEB','MAR','APR')
)
order by branch_no
;
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Author Comment

by:NiceMan331
ID: 40430342
what about week number of the year ?
0
 
LVL 31

Expert Comment

by:awking00
ID: 40430378
Same way -
select * from (
 select branch_no, trans_amount, to_char(trans_date,'WW') week
 from my_trans)
pivot
(
 sum(trans_amount)
 for week in ('01','02','03','04','05','06','07','08','09','10','11','12','13','14','15','16','17','18')
)
order by branch_no
;
0
 

Author Comment

by:NiceMan331
ID: 40430400
sorry , the pivot not working with me , i'm using oracle 9i
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Accepted Solution

by:
slightwv (䄆 Netminder) earned 500 total points
ID: 40431682
Try the code below.  You'll just need to add the rest of the months and weeks:
select branch_no,
	sum(case when to_char(trans_date,'Mon') = 'Jan' then trans_amount else 0 end) Jan,
	sum(case when to_char(trans_date,'Mon') = 'Feb' then trans_amount else 0 end) Feb,
	sum(case when to_char(trans_date,'Mon') = 'Mar' then trans_amount else 0 end) Mar,
	sum(case when to_char(trans_date,'Mon') = 'Apr' then trans_amount else 0 end) Apr
from my_trans
group by branch_no
/

select branch_no,
	sum(case when to_number(to_char(trans_date,'IW')) = 1 then trans_amount else 0 end) week_1,
	sum(case when to_number(to_char(trans_date,'IW')) = 2 then trans_amount else 0 end) week_2,
	sum(case when to_number(to_char(trans_date,'IW')) = 3 then trans_amount else 0 end) week_3,
	sum(case when to_number(to_char(trans_date,'IW')) = 4 then trans_amount else 0 end) week_4
from my_trans
group by branch_no
/

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0
 

Author Comment

by:NiceMan331
ID: 40434360
yes slightw it is ok for months
but regarding weeks , it will be very smart if you adjust the code to add start week and end week
to the beginning of the sql , then to add the weeks by for loop if you could do it
thanx
0
 
LVL 76

Expert Comment

by:slightwv (䄆 Netminder)
ID: 40435896
I do not understand what you mean by start week and end week.

Please post sample results.
0
 

Author Comment

by:NiceMan331
ID: 40435916
i mean the year has 52 weeks
instead of repeating the code 52 times
if i need only weeks between 40 and 48 for example
let the code begin loop between 40 and 48
then to add the code 8 times with increment of week number
0
 
LVL 76

Expert Comment

by:slightwv (䄆 Netminder)
ID: 40436479
If you want 8 weeks from the current date's week number try this (just keep adding weeks).

Just grab the week number from sysdate:
select branch_no,
	sum(case when to_number(to_char(trans_date,'IW')) = to_number(to_char(sysdate,'IW')) then trans_amount else 0 end) week_1,
	sum(case when to_number(to_char(trans_date,'IW')) = to_number(to_char(sysdate+7,'IW')) then trans_amount else 0 end) week_2,
	sum(case when to_number(to_char(trans_date,'IW')) = to_number(to_char(sysdate+14,'IW')) then trans_amount else 0 end) week_3,
	sum(case when to_number(to_char(trans_date,'IW')) = to_number(to_char(sysdate+21,'IW')) then trans_amount else 0 end) week_4
from my_trans
group by branch_no
/

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