How can I use a c function to determine what a string ends in?

The program is supposed to use the hydroxide function to check an inputted string to see if it ends in oh (or ho) and return a 1 value if it does. Here is what I have written and when I run the program it just freezes. I am still a beginner so I apologize in advance if this is a stupid question.

#include <stdio.h>
#include <string.h>

#define MAX_LEN 10

int hydroxide(char *compound);

	char compound[MAX_LEN];
	int i, num;
	printf("Enter compound> \n");
	scanf("%s", compound);
	for (i = 0; i < strlen(compound); ++i) {
		if (islower(compound[i]))
			compound[i] = toupper(compound[i]);
	num = hydroxide(compound);
	printf("%d", num);

int hydroxide(char *compound)
	char *end[4], *temp;
	int last, status;
	last = strlen(compound);
	strcpy(end[], &compound[last - 2]);
	if (strcmp(end[last - 2],end[last - 1]) > 0) {
		temp = end[last - 2];
		end[last - 2] = end[last - 1];
		end[last - 1] = temp;
	if (*end[last - 2] == 'H') {
		if (*end[last - 1] == 'O')
			status = 1;

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chaauConnect With a Mentor Commented:
In your hydroxide function there are a couple of problems.
First of all, temp must be declared as char, not char*
When using strcpy, use the actual variable, without []:
strcpy(end, &compound[last - 2]);

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And lastly, in the very last statement you need to check the actual characters at position [last - 2] and [last - 1], not their addresses, i.e. drop *:
if (end[last - 2] == 'H') {
		if (end[last - 1] == 'O')
			status = 1;

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what was
  strcpy(end[], &compound[last - 2]);
intended to do?
Since this is a learning exercise (either self-study or school assignment), we cannot give you complete solutions per our terms of service.

Here is a suggestion. Write a function called isOHorHOatEndOfString, which takes in the string and uses the following library function, strrchr - "Locate last occurrence of character in string"
Notice that the return values is "A pointer to the last occurrence of character in str".
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