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check passwords

Posted on 2014-11-10
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Last Modified: 2014-11-18
Im a bit stuck how to sort a problem Ive been given. Ive been asked to write a function to check a password, Ive written everything else but stuck on the rule
No 4 conservative characters from your previous 2 passwords

So something like a new password "banannas" that checks with "bana332" will fail cause "bana" exists.

Ive got the last 2 entries of passwords stored in an array, but stuck how to compare the passwords with every option.

Anyone got any pointers or sample code?????
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Question by:tonelm54
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3 Comments
 
LVL 53

Expert Comment

by:COBOLdinosaur
ID: 40433479
You can convert each of the strings to ann array with

$pass1=str_split($str1);
pass2=str_split($str2);

Loop through the array for the new pass word and compare each character to the contents of the old password with: in_array();

Cd&
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LVL 109

Expert Comment

by:Ray Paseur
ID: 40433815
No 4 conservative characters from your previous 2 passwords
Do you mean consecutive characters?  Do you have the previous 2 passwords at hand (perhaps stored in a data base table)?  If you do it's quite likely that an exposure of your data base would reveal all of the client passwords, which is why we do not store passwords in clear text.

Please tell us a little more about the assignment.  It sounds like there is something fishy going on.
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LVL 109

Accepted Solution

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Ray Paseur earned 500 total points
ID: 40434001
I don't have time to monitor this one tonight, so here is my take on a possible code example and test case.  Best of luck with it, ~Ray
http://iconoun.com/demo/temp_tonelm54.php

<?php // demo/temp_tonelm54.php
error_reporting(E_ALL);

// SEE: http://www.experts-exchange.com/Programming/Languages/Scripting/PHP/Q_28554387.html
// REF: http://php.net/manual/en/function.in-array.php
// REF: http://php.net/manual/en/function.substr.php

function in_substring($needle, $haystack, $length=4, $case=TRUE)
{
    // IF CASE-INSENSITIVE, NORMALIZE THE DATA PRIOR TO COMPARISON
    if (!$case)
    {
        $needle   = strtoupper($needle);
        $haystack = strtoupper($haystack);
    }

    // MAKE THE SUBSTRINGS OF THE NEEDLE
    while ($needle_parts[] = substr($needle, 0, $length))
    {
        $needle = substr($needle, 1);
        if (strlen($needle) < $length) break;
    }

    // MAKE THE SUBSTRINGS OF THE HAYSTACK
    while ($haystack_parts[] = substr($haystack, 0, $length))
    {
        $haystack = substr($haystack, 1);
        if (strlen($haystack) < $length) break;
    }

    // LOOK FOR NEEDLE PARTS IN THE HAYSTACK PARTS
    foreach ($needle_parts as $needle_part)
    {
        if (in_array($needle_part, $haystack_parts))
        {
            return TRUE;
        }
    }
    return FALSE;
}

// TEST CASES
$tests = array
( // FIND abc IN ABCDE case-insensitive
  (object)array
  ( 'needle'=> 'abc'
  , 'haystack' => 'ABCDE'
  , 'len' => 3
  , 'case' => FALSE
  )
, // FIND abc IN ABCDE case-Sensitive
  (object)array
  ( 'needle'=> 'abc'
  , 'haystack' => 'ABCDE'
  , 'len' => 3
  , 'case' => TRUE
  )
, // FIND thump IN thing
  (object)array
  ( 'needle'=> 'thump'
  , 'haystack' => 'thing'
  , 'len' => 4
  , 'case' => TRUE
  )
, // FIND th IN thing
  (object)array
  ( 'needle'=> 'th'
  , 'haystack' => 'thing'
  , 'len' => 2
  , 'case' => TRUE
  )
, // FIND bana IN Bananas Case-insensitive
  (object)array
  ( 'needle'=> 'BANA'
  , 'haystack' => 'BaNaNas'
  , 'len' => 4
  , 'case' => FALSE
  )
, // FIND bana IN Bananas Case-Sensitive
  (object)array
  ( 'needle'=> 'bana'
  , 'haystack' => 'Bananas'
  , 'len' => 4
  , 'case' => TRUE
  )
)
;
foreach ($tests as $test)
{
    echo PHP_EOL . '<br>';
    echo $test->needle;
    echo ' IN ';
    echo $test->haystack;
    echo '? ';
    echo "(LEN=$test->len, CASE=$test->case) ";
    echo '<b>';
    var_dump(in_substring($test->needle, $test->haystack, $test->len, $test->case));
    echo '</b>';
    echo PHP_EOL;
}

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