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FORM and Submit button display

Malloy1446
Malloy1446 asked
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Last Modified: 2014-11-10
I have a form which includes a section with a function. Based on user's input (selection of an option), user is given additional fields to complete. Right now the form is working correctly. EXCEPT, the submit button is visible before the option is selected.
User first completes some personal information.
Then, based on a selection, additional fields are displayed.
I don't want to see the submit button until after the option is selected.

I am attaching the complete code.
FORM.txt
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Big MontyWeb Ninja at large
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Commented:
first, add an ID to your submit button, so you can reference it to show/hide

<input id="btnSubmit" type="submit" value="Submit Request">

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then, either through css or javascript, hide the button on page load. below is an example using javascript/jquery since you already have it present:

	$(function()
		{
                    $('#btnSubmit').hide();

		$(" input[name='ILLRequestType']").click(function()
                     .......

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finally, add an event handler for the change event of the field. I'm unsure of which field you want to show/hide the button on, so as an example, I'm just going to attach it to a field called "fld":

<script>

	$(function()
		{
                $('#btnSubmit').hide();

		$(" input[name='ILLRequestType']").click(function()
		
		{
		var type=$(this).val();

			if(type==="Journal Article"){
				$('.chooseJournal').show();
				$('.chooseBook').hide();
 				$('.chooseAudiovisual').hide();
      
    		}
    		if(type==="Book"){
       			$('.chooseJournal').hide();
      			$('.chooseBook').show();
 				$('.chooseAudiovisual').hide();
    		
    		}
    		if(type==="Audiovisual"){
       			$('.chooseJournal').hide();
      			$('.chooseBook').hide();
 				$('.chooseAudiovisual').show();
    		}
    
})

              $(" input[name='fld']").change(function() {
                    //-- put in whatever your criteria is for showing the button. for example, if you want to make sure certain fields contain a value, you would do an IF statement here checking those fields

                 //-- your last line if the criteria is met would be
                 $('#btnSubmit').show();
            
                } else {    //-- criteria not met, hide button
                      $('#btnSubmit').hide();
                }
              });
  
})

</script>

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Author

Commented:
I need the SUBMIT button to display AFTER the user selects the "ILLRequestType".
It would display for each "ILLRequestType"

After adding an ID to the submit button, could the .show be added to the existing function or does submit button function need it's own function code.
Big MontyWeb Ninja at large
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Commented:
since that is a radio field, you should be able to show the button in the click event that you already have:

$(function()
		{
		$(" input[name='ILLRequestType']").click(function()
		
		{
		var type=$(this).val();
                $('#btnSubmit').show();

			if(type==="Journal Article"){
				$('.chooseJournal').show();
				$('.chooseBook').hide();
 				$('.chooseAudiovisual').hide();
      
    		}
    		if(type==="Book"){
       			$('.chooseJournal').hide();
      			$('.chooseBook').show();
 				$('.chooseAudiovisual').hide();
    		
    		}
    		if(type==="Audiovisual"){
       			$('.chooseJournal').hide();
      			$('.chooseBook').hide();
 				$('.chooseAudiovisual').show();
    		}
    
})
  
})

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Author

Commented:
I assigned an ID to the submit button and addded
            $('#btnSubmit').show();

to the IF statements function. The Submit button is still appearing before the user clicks on the option "ILLRequestType".

I am attaching the <script>
script.txt
Scott FellDeveloper
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Fellow
Most Valuable Expert 2013

Commented:
Malloy1446,  I updated your question topics by adding jquery and javascript and removing sql and asp.

padas
Topic Advisor
Web Ninja at large
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Commented:
This one is on us!
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