asked on

Replace string in a record

I need to replace the string values ([ILS-1] CALL: 22-03-18 SPD CALL) starting in position 15 that is 32 long with the word CALL:
I need to replace the word NORMAL with string 1,1

BEFORE
VMPIC 22:03:18 [ILS-1] CALL: 22-03-18 SPD CALL 71731,9053,9511,NORMAL,11-Nov-2014,21:55:41,21:55:41,22:03:18
VMPIC 22:03:30 [ILS-1] CALL: 22-03-30 SPD CALL 71732,9086,9509,NORMAL,11-Nov-2014,22:01:17,22:01:37,22:03:30

AFTER
VMPIC 22:03:18 CALL: 71731,9053,9511,1,1,11-Nov-2014,21:55:41,21:55:41,22:03:18
VMPIC 22:03:30 CALL: 71732,9086,9509,1,1,11-Nov-2014,22:01:17,22:01:37,22:03:30

Phillip Burton

It's actually at position 16.

See the below code:

declare @mystring nvarchar(200)
set @mystring = 'VMPIC 22:03:18 [ILS-1] CALL: 22-03-18 SPD CALL 71731,9053,9511,NORMAL,11-Nov-2014,21:55:41,21:55:41,22:03:18'

select substring(@mystring,1,15) + N'CALL: ' + replace(substring(@mystring,48,999),'NORMAL','1,1')

set @mystring = 'VMPIC 22:03:30 [ILS-1] CALL: 22-03-30 SPD CALL 71732,9086,9509,NORMAL,11-Nov-2014,22:01:17,22:01:37,22:03:30'

select substring(@mystring,1,15) + N'CALL: ' + replace(substring(@mystring,48,999),'NORMAL','1,1')

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thayduck

ASKER

This is a SQL table with 1500+ records all with different times.

ASKER CERTIFIED SOLUTION

Phillip Burton

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thayduck

ASKER

That worked, thanks.