MySQL; update on two tables

I need to replace the c.EXTRA_ID in the ccode table with the e.EXTRA_ID in the extra table.

extra
+----------------------------------------------
| EXTRA_ID | JOB_ID | JobID      | ExtraID    |
|  1000953 |  55418 | 12-15-0001 | 801        |

ccode
+------------------------------------------------------------------
| CCODE_ID | JOB_ID | EXTRA_ID | SCCODE_ID | JobID      | ExtraID |
|   803064 |  55418 |   680999 |        36 | 12-15-0001 | 801     |

UPDATE ccode c, extra e
SET c.EXTRA_ID = e.EXTRA_ID
WHERE e.JOB_ID = c.JOB_ID  AND e.ExtraID = c.ExtraID AND c.EXTRA_ID = 1000954;

When I run it it say it was successful, but it doesn't update c.EXTRA_ID

Query: update ccode c, extra e set c.EXTRA_ID = e.EXTRA_ID where e.JOB_ID = c.JOB_ID and e.ExtraID = c.ExtraID and c.EXTRA_ID = 1000953

0 row(s) affected
hdcowboyazAsked:
Who is Participating?
I wear a lot of hats...

"The solutions and answers provided on Experts Exchange have been extremely helpful to me over the last few years. I wear a lot of hats - Developer, Database Administrator, Help Desk, etc., so I know a lot of things but not a lot about one thing. Experts Exchange gives me answers from people who do know a lot about one thing, in a easy to use platform." -Todd S.

Haris DulicCommented:
Try this :

update ccode c, extra e set c.EXTRA_ID = e.EXTRA_ID where e.JOB_ID = c.JOB_ID and e.ExtraID = c.ExtraID and e.EXTRA_ID = 1000953

Open in new window


I assume the Extra_id is from Extra table so you miss typed the table synonim
0

Experts Exchange Solution brought to you by

Your issues matter to us.

Facing a tech roadblock? Get the help and guidance you need from experienced professionals who care. Ask your question anytime, anywhere, with no hassle.

Start your 7-day free trial
hdcowboyazAuthor Commented:
never mind, brain freeze. should be

UPDATE ccode c, extra e
 SET c.EXTRA_ID = e.EXTRA_ID
 WHERE e.JOB_ID = c.JOB_ID  AND e.ExtraID = c.ExtraID AND e.EXTRA_ID = 1000954;
0
hdcowboyazAuthor Commented:
Yes, thaniks
0
Vsevolod GeraskinCommented:
replace c.EXTRA_ID = 1000954; with e.EXTRA_ID = 1000954; ?
0
It's more than this solution.Get answers and train to solve all your tech problems - anytime, anywhere.Try it for free Edge Out The Competitionfor your dream job with proven skills and certifications.Get started today Stand Outas the employee with proven skills.Start learning today for free Move Your Career Forwardwith certification training in the latest technologies.Start your trial today
MySQL Server

From novice to tech pro — start learning today.

Question has a verified solution.

Are you are experiencing a similar issue? Get a personalized answer when you ask a related question.

Have a better answer? Share it in a comment.