php mysql select question

Hello,

I have:
$yfrom = 1970;
$yto = 1974;

Current select snippet:
listing_title LIKE '%".$yto."%' <- this finds all of the listings with the year in the title

and I would like it to find a range, is there a way to find a range of numbers? I am guessing that I need to break it out like

listing_title LIKE '%1970%' OR listing_title LIKE '%1971%' OR listing_title LIKE '%1972%' OR listing_title LIKE '%1973%'

is there a dynamic way to do this?

Thanks,
Matt
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movieprodwAsked:
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vr6rCommented:
Are the years in the titles always in the same place?
If so, you could try extracting them with a string function (eg: substring() if they're always in a certain spot in the middle of the title, or right(4) if they're always at the end, etc) and then compare against that value or try a BETWEEN() clause on that result for a range of years.
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NorieVBA ExpertCommented:
You could use BETWEEN or >= and <=.
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Radek BaranowskiFull-stack Java DeveloperCommented:
BETWEEN will work if column has some countable data type like int or date/timestamp

For strings only LIKE might be of use or the way author suggested himself.
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vr6rCommented:
BETWEEN will evaluate strings.  

select case when right("abc1964", 4) BETWEEN "1950" AND "1970" THEN "true" else "false" end
-----
result = "true"

select case when right("abc1964", 4) BETWEEN "1950" AND "1960" THEN "true" else "false" end
-----
result = "false"

Open in new window


The real question is if the date portion of the string can be reliably extracted from the title.  If it's in a different position within the title for each record then it would be difficult.
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Ray PaseurCommented:
Can you please show us the CREATE TABLE statement and some of your test data?
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movieprodwAuthor Commented:
Thank you for the responses, it looks like I have to rebuild how the data is stored in order to properly achieve this.
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