• Status: Solved
  • Priority: Medium
  • Security: Public
  • Views: 271
  • Last Modified:

DLast not working correctly

I'm using this code to get the last record in a table:

=DLast("[StatinsMed]","Treatment","[MemberID] = " & [Forms]![frmMemberMaster]![txtMemberID])

But it isn't working.  It's actually giving me the middle of 3 record values.

????
0
SteveL13
Asked:
SteveL13
1 Solution
 
Gustav BrockCIOCommented:
DLast and DFirst really only return "some value".

You should use DMax or DMin for the highest or lowest value.

/gustav
0
 
SteveL13Author Commented:
I guess I've been living in a cave.  I would think that DLast would give me the last records value.  DMax and DMin do not work either.
0
 
bonjour-autCommented:
asuming that the memberID is a string:

DLast("[StatinsMed]","Treatment","[MemberID] = '" & [Forms]![frmMemberMaster]![txtMemberID]) & "'"

as string needs to be wrapped in single quotes
0
What does it mean to be "Always On"?

Is your cloud always on? With an Always On cloud you won't have to worry about downtime for maintenance or software application code updates, ensuring that your bottom line isn't affected.

 
bonjour-autCommented:
withou the qoutes, the domain function filter is not valid and acts like  DLast("[StatinsMed]","Treatment","")

sorry i misstyped my first comment. it should read like:

DLast("[StatinsMed]","Treatment","[MemberID] = '" & [Forms]![frmMemberMaster]![txtMemberID] & "'")
0
 
Gustav BrockCIOCommented:
>  I would think that DLast would give me the last records value.
You can use the DFirst and DLast functions to return a random record from a particular field in a table or query when you simply need any value from that field. Use the DFirst and DLast functions in a macro, module, query expression, or calculated control on a form or report.
> DMax and DMin do not work either.
Then you will have to define the criteria for "last record".
It could be the newest value of a timestamp field.

/gustav
0
 
PatHartmanCommented:
The help entry -  http://office.microsoft.com/en-001/access-help/dfirst-dlast-functions-HA001228823.aspx explains what you get with DFirst() and DLast() and it isn't what you think it should be.  I'm not even sure what the point of having these two function is since they get lots of folks in trouble and don't seem to deliver useful results.

Keep in mind that in English, First and Last refer to ordinal position in a set.  In a relational database, tables/queries are unordered sets so First and Last have no fixed meaning since from one query to the next, First and Last could be different.  That's why the help entry says you get a random result.

As Gus suggested, tell us what you are really after and we'll see how to make Min/Max solve the problem.
0
 
Nick67Commented:
If you want order, you'll need a recordset
I suspect you are using this as a ControlSource or in a query -- so you need a public function.
In a module put

Option Compare Database
Option Explicit

Public Function LastStatinsMed as String
Dim rs as recordset

set rs = CurrentDb.OpenRecordset("Select [StatinsMed] from Treatment  where [MemberID] = " & [Forms]![frmMemberMaster]![txtMemberID] & " Order by ThePrimaryKey Desc, dbOpenDynaset, dbSeeChanges)
'whatever your primary key may be

LastStatinsMed = rs!StatinsMed
End Function

Open in new window


You can then give your control a source, or use as a query parameter
=LastStatinsMed()
instead of
=DLast("[StatinsMed]","Treatment","[MemberID] = " & [Forms]![frmMemberMaster]![txtMemberID])

To get decent performance you should avoid the use of Domain Aggregate functions in favor of similar code in all cases.
0

Featured Post

Free Tool: SSL Checker

Scans your site and returns information about your SSL implementation and certificate. Helpful for debugging and validating your SSL configuration.

One of a set of tools we are providing to everyone as a way of saying thank you for being a part of the community.

Tackle projects and never again get stuck behind a technical roadblock.
Join Now