DoCmd.GoToRecord SYNTAX

Hello ~ I'm attempting to go to a specific record on an open form using:
DoCmd.GoToRecord acDataForm, "frmProject", , "projID =" & ProjLINK

I receive: Run-time error 2498
ProjLINK is an integer
projID  is an auto-number ID and the primary key reflected on frmProject

Clearly I'm missing something here.
Would appreciate illumination!

Many Thanks!
LVL 2
Chi Is CurrentAsked:
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DatabaseMX (Joe Anderson - Microsoft Access MVP)Database ArchitectCommented:
You might try this:

docmd.GoToRecord acDataForm, "frmProject",acGoTo, "[projID] =" & CLng(me![ProjLINK])


Where is ProjLINK located ?  A field or text box on the Form ?
mx
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Gustav BrockCIOCommented:
GoToRecord is just for moving up/down the records.

For searching use:

DoCmd.SearchForRecord, "frmProject", acFirst, "projID = " & ProjLINK & ""

/gustav
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Nick67Commented:
In Access 2003, there is no SearchForRecord, there is DoCmd.FindRecord
With many records, that becomes BRUTALLY slow.

These days, I'd use
Dim db As Database
Dim rst As DAO.Recordset
Dim strCriteria As String
Dim TheprojID as Long
strCriteria = "projID = " & ProjLINK
    
'finding no match takes forever so
Set db = CurrentDb
Set rst = db.OpenRecordset("SELECT projID from WhatEverTable where " & strCriteria & ";", dbOpenDynaset, dbSeeChanges)
If rst.RecordCount = 0 Then
    response = MsgBox("No such projID found.", vbInformation)
Else
    TheprojID = rst!projID
    rst.Close
    strCriteria = "projID  = " & TheJobID
    Set rst = Me.RecordsetClone
    rst.MoveLast
    rst.FindLast strCriteria
    Me.Bookmark = rst.Bookmark
End If

Set rst = Nothing

Open in new window


It performs an order of magnitude faster than DoCmd.FindRecord once you start going north of 10K records
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Chi Is CurrentAuthor Commented:
Hello mx, /gustav & Nick67, thank you ALL for your thoughtful replies.
I am most grateful for your ideas and expertise.

Seems this is not really as much of a syntax question as a strategy question.

I think the best way of displaying the desired record is by using Nick67's method:
    ...
    rst.FindLast strCriteria
    Me.Bookmark = rst.Bookmark

Gotta give Nick67 the points for pure psychic accuracy,
this solution is perfect.

Thank you ~ Jacob
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