How to find a count of each day between two dates

I am trying to get a count of hotel nights for an upcoming meeting,  I have a table with each persons "Arrival Date" and "Departure Date" and a query with those 2 dates and the "Number of Total Nights" (used DateDiff formula).  How do I find the number of rooms I need for each night?

Ex:
Arrival Date      Departure Date      Number of Nights
3/9/2014         3/14/2014                          5
3/9/2014         3/13/2014                         4
3/10/2014         3/11/2014                         1

Number of Rooms needed for each night:  (This is the part I cant figure out how to do???)
                  
3/9/2014      3/10/2014      3/11/2014      3/12/2014      3/13/2014
2                      3                      2                      2                      1
snoopyswimerAsked:
Who is Participating?
I wear a lot of hats...

"The solutions and answers provided on Experts Exchange have been extremely helpful to me over the last few years. I wear a lot of hats - Developer, Database Administrator, Help Desk, etc., so I know a lot of things but not a lot about one thing. Experts Exchange gives me answers from people who do know a lot about one thing, in a easy to use platform." -Todd S.

Dale FyeCommented:
I generally start by creating a table (tbl_Numbers) which contains 1 field (lng_Number) and 10 records, the values 0-9.

I then create a query (qry_Numbers) that generates the numbers 0-99:
SELECT Tens.lng_Number * 10 + Ones.lng_Number as lng_Number
FROM tbl_Numbers as Tens, tbl_Numbers as Ones.

With this query, I can generate a list of 100 consecutive days:

SELECT DateAdd("d", lng_Number, [StartDate]) as MyDate
FROM qry_Numbers
WHERE DateAdd("d", lng_Number, [StartDate]) < [EndDate]

Using this as a subquery, you can include your table and generate the count of records per day.

SELECT sq.MyDate, SUM(iif(T.ArrivalDate <= sq.MyDate AND T.DepartureDate > sq.MyDate, 1, 0)) as RoomCount
FROM (
SELECT DateAdd("d", lng_Number, [StartDate]) as MyDate
FROM qry_Numbers
WHERE DateAdd("d", lng_Number, [StartDate]) < [EndDate]
) as sq, YourTable as T
GROUP BY sq.MyDate

You could refine that further so that you are not comparing the dates in the MyDate query agains all dates in your other table by filtering the other table first.  Something like:

SELECT sq.MyDate, SUM(iif(AD.ArrivalDate <= sq.MyDate AND AD.DepartureDate > sq.MyDate, 1, 0)) as RoomCount
FROM (
SELECT DateAdd("d", lng_Number, [StartDate]) as MyDate
FROM qry_Numbers
WHERE DateAdd("d", lng_Number, [StartDate]) < [EndDate]
) as sq, (
SELECT * FROM YourTable
WHERE YourTable.ArrivalDate <=[EndDate]
AND yourTable.DepartureDate >= [StartDate]
) as AD
GROUP BY sq.MyDate
0
snoopyswimerAuthor Commented:
I guess I should have mentioned that I am not great with coding. ;-)

I am going to try and mess with what you gave me and see if I can make it work.
0
Nick67Commented:
Each person has a room to themselves?
Code on a form
Option Compare Database
Option Explicit

Private Sub txtDate_AfterUpdate()
Dim rs As Recordset
Set rs = CurrentDb.OpenRecordset("Select PersonID from tblStays where arrival <= #" & Me.txtDate & "# and departure >= #" & Me.txtDate & "#;", dbOpenDynaset, dbSeeChanges)
If rs.RecordCount = 0 Then
    Me.txtRooms = 0
Else
    rs.MoveLast
    Me.txtRooms = rs.RecordCount
End If

End Sub

Open in new window


Fire up a recordset of stays that a given date falls between arrivals and departures.
The count is the number of rooms required.

Sample attached
hotels.mdb
0

Experts Exchange Solution brought to you by

Your issues matter to us.

Facing a tech roadblock? Get the help and guidance you need from experienced professionals who care. Ask your question anytime, anywhere, with no hassle.

Start your 7-day free trial
Ultimate Tool Kit for Technology Solution Provider

Broken down into practical pointers and step-by-step instructions, the IT Service Excellence Tool Kit delivers expert advice for technology solution providers. Get your free copy now.

snoopyswimerAuthor Commented:
Yes, each person has their own room.  That looks like it will work.  I actually have all my data in one table (tbl_main).  Here are the fields in that table: FirstName, LastName, EmpId (unique number), Arrival, & Departure.    Will that form / code work with just one table?
0
Nick67Commented:
Sure.
The idea is the same.
Change the line in the sample to
Set rs = CurrentDb.OpenRecordset("Select EmpId from tbl_main where arrival <= #" & Me.txtDate & "# and departure >= #" & Me.txtDate & "#;", dbOpenDynaset, dbSeeChanges)
Should git 'er dun
0
snoopyswimerAuthor Commented:
This worked perfectly!
0
Dale FyeCommented:
I'm confused.  That only returns the value for a single day, that is not what you asked in your original post.
0
Nick67Commented:
@fyed

It's not a far stretch to put multiple boxes onto a form to run it for multiple entered dates.
It's also not a far stretch to turn it into a function that you feed date in, and get # of rooms out.
Or to dummy up a form that figured out the maximum number of days between [arrival] & [departure] and to do the calculation for each day -- that's more complex as you need a dummy table to bind to get sequential numbers -- like you suggested.
Which I could have done for the Asker if requested.

But the question was "How do I find the number of rooms I need for each night"  Singular
I didn't read it as 'How do I find the number of rooms I need for each and every night"  Totality

:)

But then I always think in terms of VBA recordsets as my weapon of choice -- yours is SQL.
I thought about suggesting DCount -- but Domain Aggregates are just evil.

Nick67
0
It's more than this solution.Get answers and train to solve all your tech problems - anytime, anywhere.Try it for free Edge Out The Competitionfor your dream job with proven skills and certifications.Get started today Stand Outas the employee with proven skills.Start learning today for free Move Your Career Forwardwith certification training in the latest technologies.Start your trial today
Microsoft Access

From novice to tech pro — start learning today.

Question has a verified solution.

Are you are experiencing a similar issue? Get a personalized answer when you ask a related question.

Have a better answer? Share it in a comment.