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Hi  I want your help in understanding a java problem which iam encountering i know that you are a busy lad but it wont take a few minutes for you to guide me

Posted on 2014-11-21
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Last Modified: 2016-07-18
Hi

I want your help in understanding a java problem which iam encountering i know that you are a busy lad but it wont take a few minutes for you to guide me

The problem is suppose i entered a positive integer 8 and i have written a program to find out its divisors now

which are 1,2,4

I want to put this value in an array so suppose we have an array int [] num=i

then num[0]=1,num[1]=2 and num[2]=4

Can you please tell me how to do this

Please help me

import java.util.ArrayList;

import java.util.Scanner;

public class perfectnumber {

public static void main(String[] args) {

Scanner scan = new Scanner(System.in);

System.out.println("Please Enter a Positive number");

int num=scan.nextInt();

for(int i=1;i<num;i++){

int k=num%i;

if(k==0){

System.out.println("i="+i);

}

}

}

Regards

Kartik



"Sir,

Thanks for your Message since iam a Java beginner iam asking you these trivial issues so please excuse me for that ,Actually what i wanted to say here is if you see my program it is a program which will yield divisors but i wish to extend my program and make it into a program for evaluating perfect number (A perfect number is a algorithm in which the exact divisors of a particular number excluding the number itself totals to a particular number say for example 6 is one such number),Now my problem is here is i want to convert this variable "i" which is being calculated here into an Array so that if we calculate the divisors of fo ex somehow i[0] should be 1,i[1] should be 2 and i[2] should be 3.Can you tell me how to achieve this?"
perfectnumber.java
0
Comment
Question by:kartikeya Bajpayee
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8 Comments
 
LVL 20

Expert Comment

by:Sathish David Kumar N
ID: 40459387
Can you tell me clearly
0
 
LVL 32

Expert Comment

by:awking00
ID: 40459564
Just to clarify. Are you trying to find numbers whose divisors other than the number itself add up to the number itself? So your example of 6 would be such a number because its divisors are 1,2, and 3, which add up to 6, but 8 would not be such a number because its divisors are 1,2, and 4 which only add up to 7, correct?
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LVL 32

Expert Comment

by:awking00
ID: 40459584
Furthermore, may I assume you want an array containing those divisors?
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Author Comment

by:kartikeya Bajpayee
ID: 40460291
Guys,

Thanks for your Response

As i told you a perfect number is a program where the sum of divisors add up to the number itself

For Ex:6 has divisors as 1,2,3 other then 6 itself and the sum of these numbers accumulate to give "6" as summation

6=1+2+3

I have made a program which gives positive divisors of a certain number this number is contained in "i" My idea is to Transform i into an array so that i[0]=1,i[1]=2,i[3]=3 so that i can make a sum of it

Iam struggling a bit here on two accounts

1>I do want a fixed size for this Array
2>I want this program where i have calculated i to be transformed into an Array of integers

Can you please tell me how to do that please don't give any hints because iam a java beginner i cannot understand them explicitly

Can somebody enhance this program in this way please

Sorry but iam a beginner and have to disturb you guys because of these trivial questions

Regards

kartik
0
 
LVL 32

Accepted Solution

by:
awking00 earned 500 total points
ID: 40872414
>>Iam struggling a bit here on two accounts

 1>I do want a fixed size for this Array
 2>I want this program where i have calculated i to be transformed into an Array of integers<<

1> How can you have a fixed size for this Array? Since 6 is a perfect number, the array would look like [1,2,3]. 28 is also a perfect number, but its array would look like [1,2,4,7,14] so the Array size can not be fixed.
2> Since the Array size can not be fixed, I think you will have to use an ArrayList instead. With an ArrayList, you can just use the add method.

Incidentally, a perfect number is further defined by some prime number, p, such that the formula 2^(p -1) * (2^p - 1) results in that number.
For 6, the prime number is 2, so 2^(2-1) = 2^1 = 2 times 2^2 - 1 = 4 - 1 = 3
For 28, the prime number is 3, 2^(3-1) = 4 times 2^3 - 1 = 7
For 496, the prime number is 5, 2^4 * (2^5 - 1) = 16 * 31 = 496

The attached file should demonstrate how you might approach the problem using your method of identifying the divisors. (I actually modified your loop a little to only loop until i <= num/2 since any number greater than that can not be evenly divisible).
perfect-nums.txt
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LVL 32

Expert Comment

by:awking00
ID: 41717121
I see no reason why my comment https:#a40872414 (not sure I did this right) should not be accepted.
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