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How to find absolute extrema of 4 - abs(t - 4)
Determine the absolute extrema of the function and the x-value in the closed interval where it occurs.
h ( t ) = 4 - abs ( t - 4 )
closed interval is [ 1, 6 ]
This is not a homework problem.
This problem is from high school Advance Placement Calculus class.
h ( t ) = 4 - abs ( t - 4 )
closed interval is [ 1, 6 ]
This is not a homework problem.
This problem is from high school Advance Placement Calculus class.
SOLUTION
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SOLUTION
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ASKER CERTIFIED SOLUTION
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I hoped you first simplified h1(t) and h2(t).
You are correct.
In general, as you progress into harder functions and inequality relationships with multiple absolute value functions, the task first becomes identifying multiple partitions and then defining functions on each partition having no absolute value functions. A bit harder than this problem if the individual regions for different absolute value expressions overlap.
You are correct.
In general, as you progress into harder functions and inequality relationships with multiple absolute value functions, the task first becomes identifying multiple partitions and then defining functions on each partition having no absolute value functions. A bit harder than this problem if the individual regions for different absolute value expressions overlap.
strange.. I remember I posted something here, but I dont see now... did someone delete my post?
I dont see my post but i still get notifications? what happened to my post (and possible points)?
I dont see my post but i still get notifications? what happened to my post (and possible points)?
each partition having no absolute value functionsor more generally, each partition being monotonic.
ASKER
h2(t) = 4 - ( - t + 4); [1, 4 ]
h1 ' ( t ) = - 1
h2 ' ( t ) = 1
At t = 4, slope is undefined. There is absolute maximum at t = 4.
Am I correct ?