SQL Syntax

I have an insert statement that inserts values from an Excel spreadsheet:

insert into table (number)
values ("$Excel Column(1)$")

I would like to format the data from the spreadsheet to have leading zeros and following zeros (if that is the correct term) so that a value in the spreadsheet that appears as 2.02 would be stored in the number field as 02.020.  The data field is specified as nvarchar so that it can hold the numbers and the period.  I tried to format the column of cells in Excel but the formatting did not hold on the insert.  The format (number,00.000) does not work in the SQL code.

Not sure what to do.
mounty95Asked:
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Vitor MontalvãoMSSQL Senior EngineerCommented:
I personally don't like to use SQL Server for formatting. For be a database it's only for store data and the formatting should be with the application layer.
Anyway, you can use RIGHT function:
insert into table (number)
 values (RIGHT('00'+ CONVERT(VARCHAR,"$Excel Column(1)$"),3)) 

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Jim HornMicrosoft SQL Server Developer, Architect, and AuthorCommented:
>I would like to format the data from the spreadsheet to have leading zeros and following zeros
Spell out for us at Barney-level why you want this, and specifically why it has to be inserted into the table this way.

You can always write T-SQL code to format it with leading zeros for various reports, but it's not considered a best practice to store numbers with leading zeros as a varchar.  Now if all you're doing is storing the values, and not performing any math on them, then different story.

>I tried to format the column of cells in Excel but the formatting did not hold on the insert.
Is data moving FROM Excel TO SQL Server, or the other way around?
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HainKurtSr. System AnalystCommented:
why this should be so ugly?

declare @n float = 2.03;
select substring('00' + cast (@n as varchar) + '000', charindex('.', '00' + cast (@n as varchar))-2, 6)

02.030
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HainKurtSr. System AnalystCommented:
table (number)

so table column datatype is numeric? or varchar(6)?
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Scott PletcherSenior DBACommented:
REPLACE(STR([$Excel Column(1)$], 6, 3), ' ', '0')

Or, more fully:

insert into table1 (number)
values (REPLACE(STR([$Excel Column(1)$], 6, 3), ' ', '0'))

For example:
 select [$Excel Column(1)$],REPLACE(STR([$Excel Column(1)$], 6, 3), ' ', '0')
 from (
     select 2.02 as [$Excel Column(1)$] union all
     select 0.05 union all
     select 21.3 union all
     select 7
     ) as test_data
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mounty95Author Commented:
I have data in other databases where the data has been stored 00.000 and I need to be able to perform joins on this field.

The data is in an Excel spreadsheet and going to SQL.

I am not sure what "Barney-level" means, but i am simply trying to have the data in a format similar to other databases that I would join on.
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HainKurtSr. System AnalystCommented:
the code I posted ^^^ is what you are trying to get... ugly but it should work as long as your input is correct...
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mounty95Author Commented:
The column that the data is inserted into is nvarchase because the value is two digits, a period, and three digits with leading zeros and zeros on the end to make it three digits after the period.

HainKurt, not sure how to integrate your code into an insert.
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HainKurtSr. System AnalystCommented:
should be like:

insert into table (number)
 values (substring('00' + cast (@n as varchar) + '000', charindex('.', '00' + cast ("$Excel Column(1)$" as varchar))-2, 6)
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mounty95Author Commented:
HainKurt, I am not sure I follow your logic.  I get a substring function requires 3 arguments error when trying to copy your code into my example.  I added a declare line before the insert command, but not sure how that applies to dynamically getting a value out of the spreadsheet.

Can you clarify please?
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HainKurtSr. System AnalystCommented:
you said you are using this:

insert into table (number)
values ("$Excel Column(1)$")

if this works, then this one should work too:

insert into table (number)
values (substring('00' + cast ("$Excel Column(1)$" as varchar) + '000', charindex('.', '00' + cast ("$Excel Column(1)$" as varchar))-2, 6)

i forgot to replace some test variable here :)
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