Concaenate field that needs to be 30 characters long

Hi there,
I have the following statement:
select 
REPLACE(concat(glje_ref1,glje_ref2, glje_ref3, glje_ref4), ' ', '')
from mytable

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and this returns a string with different lengths. What I need to do is to return the first 30 Characters it is ok if the trailing character are cut of
what's the best practice on going about this?
Thanks
COHFLAsked:
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Aneesh RetnakaranDatabase AdministratorCommented:
select LEFT (REPLACE(concat(glje_ref1,glje_ref2, glje_ref3, glje_ref4), ' ', '') , 30 )
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COHFLAuthor Commented:
Im thinking on
SUBSTRING(REPLACE(concat(glje_ref1,glje_ref2, glje_ref3, glje_ref4), ' ', '')
, 1, 30)

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Jim HornMicrosoft SQL Server Developer, Architect, and AuthorCommented:
Either of these will work, as they both return a 30-character varchar:
select CAST(REPLACE(concat(glje_ref1,glje_ref2, glje_ref3, glje_ref4), ' ', '') as varchar(30)) 
from mytable

select LEFT(REPLACE(concat(glje_ref1,glje_ref2, glje_ref3, glje_ref4), ' ', ''), 30) 
from mytable

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0
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COHFLAuthor Commented:
they all worked but one thing I guess I did not account it for is when there is not data under any of the refs or the string is less than 30 the replace kick in and remove empty spaces. and if the string is less said 20 characters I need it to be 30 characters long how do I achieve this?
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Aneesh RetnakaranDatabase AdministratorCommented:
select LEFT (REPLACE(concat(glje_ref1,glje_ref2, glje_ref3, glje_ref4), ' ', '')+replicate('-',30 )  , 30 )
0

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Jim HornMicrosoft SQL Server Developer, Architect, and AuthorCommented:
>I need it to be 30 characters long
In that case CAST it as a CHAR instead of VARCHAR.  
To demonstrate copy-paste the below code into your SSMS and execute.
Declare @val varchar(50) = '12345678901234567890'

SELECT DATALENGTH(CAST(@val as char(30)))
SELECT DATALENGTH(CAST(@val as varchar(30)))
SELECT DATALENGTH(LEFT(@val, 30))

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