Solved

Get files between two dates, Linux RedHat

Posted on 2014-11-26
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333 Views
Last Modified: 2014-11-27
Hi Experts,
I would write a script to make a copy (scp) of all Transfer_data files. * From a path, which were generated from the current time (DATE) and 1 minute backward.
Example:
hostname: / path /> date
Wed November 26 2014 16:53:00 ART
hostname: / path /> ls -t1 Transfer_data *.
Transfer_data.20141126165232
Transfer_data.20141126165203
Transfer_data.20141119165103
Transfer_data.20141119165003
Transfer_data.20141119164909
Transfer_data.20141119164801

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I wish to copy only:
Transfer_data.20141126165232
Transfer_data.20141126165203

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and after a minute, rerun the script, taking only the files generated during that minute
Example2:
hostname: / path /> date
Wed November 26 2014 16:54:00 ART
hostname: / path /> ls -t1 Transfer_data *.
Transfer_data.20141126165332
Transfer_data.20141126165303
Transfer_data.20141126165232
Transfer_data.20141126165203

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I wish to copy only:
Transfer_data.20141126165332
Transfer_data.20141126165303

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I know how to use the cron tool, but I have trouble generating the ranges in a script.
I tried to start with:
#!/bin/ksh
touch -t date --date "1 minute ago"  start
touch -t date end
find . \( -newer inicio -a \! -newer fin \) -exec ls -l  {} \;

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You would have any examples that I can use?
Would appreciate any idea how.
Thank you very much
Regards
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Comment
Question by:carlino70
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7 Comments
 
LVL 68

Expert Comment

by:woolmilkporc
ID: 40467681
Wouldn't it be easier to remove the already scp'ed files from the relevant directory so you can transfer all new files at each run?
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LVL 68

Expert Comment

by:woolmilkporc
ID: 40467695
To list the files whose names correspond to the previous minute you can use this:

ls -t1 Transfer_data.$(date -d "1 minute ago" "+%Y%m%d%H%M")*

The above works only with GNU date (standard on Linux).

Please be aware that percent signs (%) used in crontab (not in scripts called by cron!) must be escaped by means of a backslash (\)
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LVL 68

Accepted Solution

by:
woolmilkporc earned 250 total points
ID: 40467733
Again, your own script is not at all wrong but just needs corrections:

#!/bin/ksh
touch -t $(date --date "1 minute ago" "+%Y%m%d%H%M.00") start
# 1 minute backward only:
touch -t $(date --date "1 minute ago" "+%Y%m%d%H%M.59") end
# Current minute and 1 minute backward:
# touch -t $(date "+%Y%m%d%H%M.59") end
find . -name "Transfer_data*" -type f \( -newer start -a \! -newer end \) -print |sort -r

"ls -l" will give way too much info, so I used "-print" and "sort -r" to get the (by name) newest file on top.
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LVL 40

Assisted Solution

by:omarfarid
omarfarid earned 250 total points
ID: 40468313
I would run something like:

mystart=start$$
myend=end$$
touch $mystart
sleep 60
touch $myend
find . -name "Transfer_data*" -type f \( -newer $mystart -a \! -newer $myend \) -print |sort -r

This should give files that were created in last minute
0
 

Author Comment

by:carlino70
ID: 40468712
If it should be easier, but I can not delete files from the original directory. Move them to a temporary folder and then transfer would be an option, but would require more time in the process.
0
 

Author Comment

by:carlino70
ID: 40468852
omarfarid, woolmilkporc:

I'll test both ideas.

Thanksyou
0
 

Author Closing Comment

by:carlino70
ID: 40469260
Thanks, both solutions work
0

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