Return 0.00 where there is no records

I have two tables, an GL_ACCT table and a GL_Trans table.

I'm trying to determine the closing balance for a ledger account that had no transactions is a particular month but with an opening balance of 400.

The problem I am having is that when I select records from the transaction table, the ledger ID I'm keen to see doesn't return a value of '0.00' which I expect knowing there are no records, but does have an opening balance. It just give me two records instead of four.

LD_ID       OPENING BALANCES             MOVEMENT                                      CLOSING BALANCES        
                 DR                       CR                     DR                      CR                                 DR                     CR
  2           449,999.60      0.00                633,396.60      483,396.60                 599,999.60             0.00
  4         150,000.00      0.00                     200,000.00      150,000.00                 200,000.00             0.00

Basically this is what I trying to achieve is this:

LD_ID       OPENING BALANCES             MOVEMENT                                      CLOSING BALANCES        
                 DR                       CR                     DR                      CR                                 DR                     CR
  2           449,999.60      0.00                633,396.60      483,396.60                 599,999.60             0.00
  3         0.00                      0.00                     0.00                      0.00                                 0.00                     0.00
  4         150,000.00      0.00                     200,000.00      150,000.00                 200,000.00             0.00
  7        200,000.00        0.00                     0.00                      0.00                                 200,000.00             0.00
barkomeAsked:
Who is Participating?
I wear a lot of hats...

"The solutions and answers provided on Experts Exchange have been extremely helpful to me over the last few years. I wear a lot of hats - Developer, Database Administrator, Help Desk, etc., so I know a lot of things but not a lot about one thing. Experts Exchange gives me answers from people who do know a lot about one thing, in a easy to use platform." -Todd S.

Vikas GargBusiness Intelligence DeveloperCommented:
Hi,

You can use the left join in place of inner join

and after that you can use case statement to remove null from '0.00'
0
Vitor MontalvãoMSSQL Senior EngineerCommented:
Can you post the query that you are using now?
0
barkomeAuthor Commented:
Hi Vitor

This is what Im using...

SELECT A.LD_ID, B.BAL FROM
(SELECT                  GA.LD_ID L_ACCT_ID, GL.LD_ID, GL.PROD, GA.CHRT_ID, GA.LD_DC,
                                                SUM(CASE WHEN GL.TDM = '0' THEN -GL.TMT ELSE 0 END) AS DR,
                                                SUM(CASE WHEN GL.TDM = '1' THEN GL.TMT ELSE 0 END) AS CR,
                                                GL.SRC_SYS
                        FROM                  GL, GA GA
                        WHERE                  GA.LD_ID = GL.LD_ID AND GL.EFF_DT >= '01-OCT-2014' AND GL.EFF_DT <= '31-OCT-2014'
                        AND                        GL.LD_ID IN ('ID_1','ID_2','ID_3','ID_4')
                        GROUP BY            GA.LD_ID, GL.LD_ID, GL.PROD,GA.LD_DC, GA.CHRT_ID, GL.SRC_SYS) A,

(SELECT         GL.LD_ID,            (SUM(CASE WHEN GL.TDM = '0' THEN -GL.TMT ELSE 0 END)) + (SUM(CASE WHEN GL.TDM = '1' THEN GL.TMT ELSE 0 END)) OPN_BAL
                        FROM                  GL GL WHERE GL.EFF_DT <= '01-OCT-2014'
                        AND                  LD_ID IN ('ID_1','ID_2','ID_3','ID_4')
                        GROUP BY            GL.LD_ID )B

WHERE A.LD_ID = B.LD_ID AND B.LD_ID IN ('ID_1','ID_2','ID_3','ID_4')
0
Cloud Class® Course: Microsoft Windows 7 Basic

This introductory course to Windows 7 environment will teach you about working with the Windows operating system. You will learn about basic functions including start menu; the desktop; managing files, folders, and libraries.

barkomeAuthor Commented:
Hi Vikas

Tried the left join that you suggested, it returned no records
0
Vitor MontalvãoMSSQL Senior EngineerCommented:
The SUM doesn't process NULL values. For that you need to use the ISNULL function to assume NULL values as zero:
SELECT A.LD_ID, B.BAL 
FROM (SELECT  GA.LD_ID L_ACCT_ID, GL.LD_ID, GL.PROD, GA.CHRT_ID, GA.LD_DC,
              SUM(CASE WHEN GL.TDM = '0' THEN -ISNULL(GL.TMT,0) ELSE 0 END) AS DR,
              SUM(CASE WHEN GL.TDM = '1' THEN ISNULL(GL.TMT,0) ELSE 0 END) AS CR,GL.SRC_SYS
		FROM GL, GA GA
        WHERE GA.LD_ID = GL.LD_ID AND GL.EFF_DT >= '01-OCT-2014' AND GL.EFF_DT <= '31-OCT-2014'
			AND GL.LD_ID IN ('ID_1','ID_2','ID_3','ID_4')
        GROUP BY GA.LD_ID, GL.LD_ID, GL.PROD,GA.LD_DC, GA.CHRT_ID, GL.SRC_SYS) A, 
	(SELECT GL.LD_ID, (SUM(CASE WHEN GL.TDM = '0' THEN -ISNULL(GL.TMT,0) ELSE 0 END)) + (SUM(CASE WHEN GL.TDM = '1' THEN ISNULL(GL.TMT,0) ELSE 0 END)) OPN_BAL
	FROM GL GL 
	WHERE GL.EFF_DT <= '01-OCT-2014' AND LD_ID IN ('ID_1','ID_2','ID_3','ID_4')
	GROUP BY GL.LD_ID )B
 WHERE A.LD_ID = B.LD_ID AND B.LD_ID IN ('ID_1','ID_2','ID_3','ID_4') 

Open in new window

0

Experts Exchange Solution brought to you by

Your issues matter to us.

Facing a tech roadblock? Get the help and guidance you need from experienced professionals who care. Ask your question anytime, anywhere, with no hassle.

Start your 7-day free trial
barkomeAuthor Commented:
Hi Guys

Has to also add ISNULL at the select clause when also retrieving at that level
0
Vitor MontalvãoMSSQL Senior EngineerCommented:
So, why my solution isn't "acceptable"?
0
barkomeAuthor Commented:
Hi Vitor

I tried to accept multiple solutions, don't know why the two didn't reflect..(it's been a while since I used EE)
0
Vitor MontalvãoMSSQL Senior EngineerCommented:
You can request for an EE moderator to help you with that.
0
barkomeAuthor Commented:
O that's great, how do I do that?.
0
Vitor MontalvãoMSSQL Senior EngineerCommented:
At the top of this question there's a Requestion Attention link. Just click on it.
Thanks.
0
It's more than this solution.Get answers and train to solve all your tech problems - anytime, anywhere.Try it for free Edge Out The Competitionfor your dream job with proven skills and certifications.Get started today Stand Outas the employee with proven skills.Start learning today for free Move Your Career Forwardwith certification training in the latest technologies.Start your trial today
Microsoft SQL Server 2008

From novice to tech pro — start learning today.

Question has a verified solution.

Are you are experiencing a similar issue? Get a personalized answer when you ask a related question.

Have a better answer? Share it in a comment.