We help IT Professionals succeed at work.

display id in connect prior sql

chalie001
chalie001 asked
on
128 Views
Last Modified: 2014-12-20
hi how can i diplsay the id of

obj_name

obj_parent

obj_child

and make sure there is no duplicate in obj_name column


WITH hierarchical AS (  

      SELECT  obj_parent

            , li.obj_name  

           , li.obj_type  

           , li.obj_title              , li.DESCRIPTION    

            , LEVELAS lvl

           , SYS_CONNECT_BY_PATH(li.obj_name, '/')paths    

        FROM object_list li  

        LEFTJOIN cal_erd er ON (li.cal_objid = er.obj_child)

           START WITH obj_parent IS NULL  

          CONNECTBY    

                  NOCYCLE PRIOR cal_objid = obj_parent

                   )                        

, childs_parents AS (

              SELECT  obj_name

                    , LEAD(obj_name) OVER(PARTITION BY substr(paths, 1 ,

                                          CASEWHEN INSTR(paths, '/', 1, 2) > 0

                                               THEN INSTR(paths, '/', 1, 2) -1

                                                ELSE LENGTH(paths)

                                           END)ORDERBY paths) AS child_name

                    , substr(paths,                          

                                  INSTR(paths, '/', 1, CASEWHEN lvl > 1 THEN lvl-1 END) + 1 ,    

                                  INSTR(paths, '/', 1, CASEWHEN lvl > 1 THEN lvl END)                      

                                - INSTR(paths, '/', 1, CASEWHEN lvl > 1 THEN lvl-1 END) - 1 ) AS parent_name

                   , obj_type    

                    , obj_title  

                    , DESCRIPTION    

                  

              FROM hierarchical

              )

SELECT *  

  FROM childs_parents;

Open in new window


i what to display value like this
OBJ_CHILD    CHILD_ID    OBJ_ID    OBJ_NAME         OBJ_PARENT    PARENT_ID

ThirdObject      1194         1 193        SecondObject    MainObject    1 192

FourthObject    1195        1 194        ThirdObject        SecondObject   1 193

                          1195                               FourthObject    ThirdObject    1 194

                         1196                               FirthObject      

SecondObject  1193              1 192       MainObject
Comment
Watch Question

CERTIFIED EXPERT
Top Expert 2013
Commented:
This one is on us!
(Get your first solution completely free - no credit card required)
UNLOCK SOLUTION

Author

Commented:
correct

Author

Commented:
hi I will like to concaternate connect prior return values to look like this from above query
    Obj_Name       child_name      Parent_name

    MainObject     ThirdObject    (null)

    SecondObject   FourthObject    MainObject

    FourthObject   ThirdObject     SecondObject

    ThirdObject    ThirdObject     SecondObject,MainObject

or

Gain unlimited access to on-demand training courses with an Experts Exchange subscription.

Get Access
Why Experts Exchange?

Experts Exchange always has the answer, or at the least points me in the correct direction! It is like having another employee that is extremely experienced.

Jim Murphy
Programmer at Smart IT Solutions

When asked, what has been your best career decision?

Deciding to stick with EE.

Mohamed Asif
Technical Department Head

Being involved with EE helped me to grow personally and professionally.

Carl Webster
CTP, Sr Infrastructure Consultant
Empower Your Career
Did You Know?

We've partnered with two important charities to provide clean water and computer science education to those who need it most. READ MORE

Ask ANY Question

Connect with Certified Experts to gain insight and support on specific technology challenges including:

  • Troubleshooting
  • Research
  • Professional Opinions
Unlock the solution to this question.
Join our community and discover your potential

Experts Exchange is the only place where you can interact directly with leading experts in the technology field. Become a member today and access the collective knowledge of thousands of technology experts.

*This site is protected by reCAPTCHA and the Google Privacy Policy and Terms of Service apply.

OR

Please enter a first name

Please enter a last name

8+ characters (letters, numbers, and a symbol)

By clicking, you agree to the Terms of Use and Privacy Policy.