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oracle sql analytics

Posted on 2014-12-04
Medium Priority
Last Modified: 2015-02-16
i have a table which records students preferences. i need to flag up the students who have only preferenced 20, 21 or 22.
the table below shows the output from the pref table (2 columns), and the output shows the desired output.

select * from pref			output					
student	preference		student	only_20_21_22				
1		1				1		n
1		2				2		n
1		3				3		y
2		1				4		n
2		2				5		y
3		20				6		n
4		21				7		n
4		22				8		y
4		1				9		n
4		2				10		n
5		20						
5		22						
5		21						
6		1						
6		2						
7		1						
7		20						
8		20						
9		20						
9		1						
9		2						
9		22						
10		2						

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any help is appreciated
Question by:tonMachine100

Expert Comment

by:Ahmed Merghani
ID: 40480446
Try this:
Select student, CASE 
            WHEN preference = 20 or preference = 21 or preference = 22 
               THEN 'y' 
               ELSE 'n' 
       END as only_20_21_22 from pref

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LVL 14

Expert Comment

by:Alexander Eßer [Alex140181]
ID: 40480461
select p.student,
       case regexp_count(listagg(p.preference, ',') within group(order by p.student), '^20|^21|^22')
         when 1 then
       end only_20_21_22
  from pref p
 group by p.student
 order by p.student;

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LVL 14

Expert Comment

by:Alexander Eßer [Alex140181]
ID: 40480464
@Ahmed Merghani: Please see the asker's expected results! Your statement will not work upon what he asked for...
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LVL 79

Assisted Solution

by:slightwv (䄆 Netminder)
slightwv (䄆 Netminder) earned 1000 total points
ID: 40480578
Assuming the sample data provided is not a complete sample and the following data is possible:
student, preference

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The above query will also fail.

Building on it try this:
select p.student,
	case when ltrim(regexp_replace(listagg(p.preference, ',') within group(order by p.student),'2[012]'),',') is null then 'y' else 'n' end 
  from pref p
 group by p.student
 order by p.student;

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LVL 14

Expert Comment

by:Alexander Eßer [Alex140181]
ID: 40480598
Yes, slightwv's regex will work better upon the (sample) data provided...
LVL 32

Accepted Solution

awking00 earned 1000 total points
ID: 40480872
select student,
min(case when not regexp_like(preference,'2[012]') then 'n' else 'y' end) student_only_20_21_22
from pref
group by student
order by student;
LVL 79

Expert Comment

by:slightwv (䄆 Netminder)
ID: 40480890
Knew there had to be a cleaner way...

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