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Excel Row Deletion Based on Fill

Oh great and knowledgeable people of EE:

I want to add a little bit of code to an existing Excel macro that will do the following.
1) Select all content.
2) Review each line individually to determine if the row contains a cell with the default gold fill.
3) If the row does NOT contain a cell with gold fill, the row should be deleted.
4) The code then moves through the remaining content, repeating the deletion process for all rows that do not contain a cell with gold fill.

The end result is that only rows that contain at least one cell with gold fill remain.

As always, your assistance is greatly appreciated.
1 Solution
an existing Excel macro
Do you already have looping/filtering code in place that can be flanged in?
Select all content.
Is there a set row & column count?  Rows only, Columns only?

You can build loops to check each cell row by row, but that is ugly-slow code if the sheet is huge.
More detail, and a sample are a good idea!
behestAuthor Commented:
Thank you for considering my latest challenge. Attached is an example of the basic functionality of the macro. After running the macro, there is one column sorted by color. But another column also contains gold filled cells. All I really want to be left at the end of the process is the rows that have gold cells.
Sub Macro1()
Dim i As Long
Dim r As Range

Set r = ActiveSheet.Range("B1:B200")
For i = r.Cells.Count To 1 Step -1
    If r.Cells(i).Interior.ColorIndex = 6 Then
        r.Cells(i).EntireRow.Delete shift:=xlUp
    End If
Next i

End Sub

Open in new window

Change ActiveSheet.Range("B1:B200") to be the cells you want to detect.
Also double check the ColorIndex.
6 = Yellow.
Record a Macro changing the colour and use that colour index
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This is the best I can do for you:
Define a function
Function IntColor(rng As Range) As Long
IntColor = rng.Interior.Color
End Function

Now, in the last column, whether by VBA or by hand add a formula
The formula for Row 2, last cell would be
=or(IntColor(c2) = 49407,IntColor(D2) = 49407)

Then filter by that row = False
The delete all visible rows and remove the filter

behestAuthor Commented:
Hmmmm...neither of these options quite gets me where I want to be at the end. So, how about this option?

Instead of a filter, I apply a tiered sort, where the sort is made by cell color.

Sub GoldMacro()
' GoldMacro Macro

    With Application.ReplaceFormat.Interior
        .PatternColorIndex = x1Automatic
        .Color = 49407
        .TintAndShade = 0
        .PatternTintAndShade = 0
    End With
    Cells.Replace What:="Acrid", Replacement:="Acrid", LookAt:=xlPart, _
        SearchOrder:=xlByRows, MatchCase:=False, SearchFormat:=False, _
    Cells.Replace What:="Hemp", Replacement:="Hemp", LookAt:=xlPart, _
        SearchOrder:=xlByRows, MatchCase:=False, SearchFormat:=False, _

    ActiveWorkbook.Worksheets("Gold").Sort.SortFields.Add(Range("D2:D21"), _
        xlSortOnCellColor, xlAscending, , xlSortNormal).SortOnValue.Color = RGB(255, _
        192, 0)
    ActiveWorkbook.Worksheets("Gold").Sort.SortFields.Add(Range("C2:C21"), _
        xlSortOnCellColor, xlAscending, , xlSortNormal).SortOnValue.Color = RGB(255, _
        192, 0)
    With ActiveWorkbook.Worksheets("Gold").Sort
        .SetRange Range("A1:F21")
        .Header = xlYes
        .MatchCase = False
        .Orientation = xlTopToBottom
        .SortMethod = xlPinYin
    End With
End Sub

So, now all that remains to be done is to code the following:

-- Identify the last row with a gold fill applied.
-- Select the rows beneath the last row with gold fill.
-- Delete selected rows.
Or invert your sort.  Everything WITHOUT gold to the top.
Then you can kill everything from row 1 to the first gold cell
That might be more efficient than locating last cell -- which can be notoriously imprecise.
Martin LissRetired ProgrammerCommented:
This question has been classified as abandoned and is closed as part of the Cleanup Program. See the recommendation for more details.

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