Counting num ber of days using tsql

I have a transaction table that holds CID, status and transaction date. Status can be o, c , r.
A CID can go from o to c to r to c.

For each CID I want to find the duration it has been in o or r, and store it in a target table.

Please help me on how I can accomplish this using tsql, possibly without a cursor. I want to track number of days from o to c and r to c. If a CID is not in c status after being in o or r then it is considered to be in the same status till current date.

Sample data copied below and also attached as a worksheet.

Transaction table data:
1      o      12/1/2014
2      o      12/2/2014
3      o      12/3/2014   --3 o no c: 9 days till today
1      c      12/3/2014   --1 o to c: 12/1/2014 to 12/3/2014 = 1 day
1      r      12/4/2014  
2      c      12/4/2014   --2 o to c: 12/2/2014 to 12/4/2014 = 2 days
1      c      12/5/2014   --1 r to c: 12/4/2014  to 12/5/2014 = 1 day
1      r      12/10/2014 --1 r no c: 12/10/2014 to today = 2 days

Target table: has one row per CID+status
CID      status      DurationInDays
1      o             2
1      r              3  (1+2)
2      o              2
3      o              9


Thank you for your help.
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I see you have chosen SQL 2008 as the topic but is that the version you actually use?
in particular do you use SQL 2012 or later?

Is there s unique ID for each row in this table?
What is the table's name.?
Brendt HessSenior DBACommented:
Your data source must have uniquely identifiable rows for any such calculation to work.  For my work, I created and populated a simple temp table:

    CID int NOT NULL,
    status char NULL,
    transdate datetime,
    seq int IDENTITY(1, 1)

INSERT INTO #tt (cid, status, transdate) VALUES (1, 'o', '12/1/2014')
INSERT INTO #tt (cid, status, transdate) VALUES (2, 'o', '12/2/2014')
INSERT INTO #tt (cid, status, transdate) VALUES (3, 'o', '12/3/2014')
INSERT INTO #tt (cid, status, transdate) VALUES (1, 'c', '12/3/2014')
INSERT INTO #tt (cid, status, transdate) VALUES (1, 'r', '12/4/2014')
INSERT INTO #tt (cid, status, transdate) VALUES (2, 'c', '12/4/2014')
INSERT INTO #tt (cid, status, transdate) VALUES (1, 'c', '12/5/2014')
INSERT INTO #tt (cid, status, transdate) VALUES (1, 'r', '12/10/2014')

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This method worked well to get your data out in the form you needed.

;WITH tf AS (
        MAX(seq) AS seq,
                SELECT MIN(transdate) 
                FROM #tt AS tX 
                WHERE tX.CID = #tt.CID 
                    AND tX.transdate > #tt.transdate
                CONVERT(varchar(10), CURRENT_TIMESTAMP, 101)
           ) AS nextDt
    FROM #tt
    GROUP BY cid, 

    SUM(DATEDIFF(DAY, tf.transdate, tf.nextDt)) AS durationInDays
    ON tf.CID = t.CID
    AND tf.seq = t.seq
WHERE t.status IN ('o', 'r')

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patd1Author Commented:
Thank You bhess1. That seems to be working. Can you please explain the logic in simple words so I can understand.

Thanks a lot again.
patd1Author Commented:
Thank You.
Brendt HessSenior DBACommented:
The WITH statement creates a virtual table consisting of (1) The CID, Transaction date, the latest transaction ID for that CID/Transaction date, and the next date a transaction with that CID occurs on, or the current date if there is no other record with that CID on a later date.

The output of the WITH statement is essentially another table. So we join that output back to the original source table by CID and Seq, and use the pair of dates in the WITH table to calculate the duration of the activity.
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Microsoft SQL Server 2008

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