Create a class property using a variable.

I have a class and it has properties defied for creating an xml file.

I have another xml file which defines all the different elements information for the xml file generation for different kind of feeds.

See my code below.

Here i am reading a feed structure xml file.
I have a dictionary which has the element values for the xml file.
I am reading the structure xml file by tags and reading all the elements under those tags.
I have a loop here and comparing xml element with dictionary element and when both matches, i have to assign dictionary value to the class property.

I have class properties defined like xml.Library, xml.Application etc.

Suppose when both childNode.InnerText == dict.ElementAt(i).Key.ToString() matches

i have assign them like xml.Library = dict.ElementAt(i).Key.ToString().

But instead of specifying xml.Library i want to make it dynamic by specifying like

string str = dict.ElementAt(i).Key.ToString();
  "xml." + str = dict.ElementAt(i).Value.ToString();

Anyone has any suggessions, needed help it urgently. Thanks

 string strFile = "di-feedstructure.xml";
AIXML xml = new AIXML();
  XmlDocument xmldoc = new XmlDocument();
 xmldoc.Load(AppDomain.CurrentDomain.BaseDirectory + strFile);
 List<XmlNode> nodes = xmldoc.GetElementsByTagName("DiConfig").Cast<XmlNode>().ToList();
 foreach (XmlNode node in nodes)
 {
      if (node.Attributes["Feed"].InnerText == sfeed)
                    {
                        foreach (XmlNode childNode in node.ChildNodes)
                        {
                            if (childNode.InnerText != "")
                            {
                                for (int i = dict.Count - 1; i >= 0; i--)
                                {
                                    if (childNode.InnerText == dict.ElementAt(i).Key.ToString())
                                    {
                                        string str = dict.ElementAt(i).Key.ToString();

                                        "xml." + str = dict.ElementAt(i).Key.ToString();
                                    }
                                }
                            }
                        }
                        xml.CreateXML(dirname, documentName);
                    }
                }

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Thanks